The sum of two numbers, a and b, is 12. The first number, a, is 8 more than the second number
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I'm still confused
HOW R U CONFUSED
first step is to translate it
a + b = 12 sum of two numbers, a& b, is 12
a = b + 8 1st number a is 8 more than 2nd
now I would use substitution to solve. Can you finish it?
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so it'd be like 12 = (b + 8) + b
[since a = b+ 8] right?
combine like terms: 12 = 2b + 8
use transposition 12 - 8 = 2b
[therefore: 4 = 2b ]
then divide by 2 [ 4/2 = 2b/2]
so b = 2;
now substitute b = 2 to find a [12 = a + 2]
should I also answer that?
Shouldn't it be 4 because 4+8=12
It has to be 2+10 because 10 is eight greater than 2.
no, @calculusxy, it is not 4 since the other term is 8 and remember we stated before that 8 - 4 should be 8? well, it is not, so we will have to look to other numbers then!
But yes it is 10 :) simply put, we explain this by getting the other term: 2 (since 10 + 2 is indeed 12) and we notice that it also fits the other requirement: 10 - 2 = 8 :) so yay! you solved it :)
hope this helped! have a great day :)