anonymous
  • anonymous
solve log32 x=-2/5 solve logx 9=-1/2 solve log1/2 32=x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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cwrw238
  • cwrw238
log32 x=-2/5 means that x = 32 ^ (-2/5) can you continue?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
so x=.25?

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cwrw238
  • cwrw238
yes 1 / (32^0.2)^2 = 1 / 2^2 = 1/4 0r 0.25
anonymous
  • anonymous
ok thanks so much!
cwrw238
  • cwrw238
yw
anonymous
  • anonymous
so the second one 9=x^(-1/2) how do you get the answer?
cwrw238
  • cwrw238
9 = 1 --- x^(1/2) x^(1/2) = 1/9 now square both sides x = (1/9)^2
anonymous
  • anonymous
do you do the same thing for the third one?
cwrw238
  • cwrw238
to get rid of the log function use : if loga b = x then b = a^ x or if you find this difficult to remember use : if log10 100 = 2 then 100 = 10^2 you now the last part is true so its a check that you have it right
cwrw238
  • cwrw238
for the third one you get (1/2)^x = 32 in this case take logs to the base e and use your calculator ln (0.5)^x = ln 32 x* ln(0.5) = ln 32 x = ln32 / ln(0.5)
anonymous
  • anonymous
x=-5?

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