anonymous
  • anonymous
4. Ethylene glycol (C2H6O2) is used as an antifreeze in cars. If 400 g of ethylene glycol is added to 4.00 kg of water, what is the molality? Calculate how much the freezing point of water will be lowered. The freezing-point depression constant for water is Kf = –1.86°C/m. Show your work.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
ok, so first calculate the molality which is just moles solute/kg solvent... to get the moles solute, you just divide the grams of ethylene glycol by its molecular weight. to obtain the freezing point depression, use the eqn deltaTf = (molality)(Kf).... basically, just multiply the molality you computed to the given Kf...
anonymous
  • anonymous
molar mass of ethylene glycol = 62g mass of ethylene glycol = 400g mass of solvent (in kg) = 4kg molality = \[400/(62*4)\] =1.61m delta Tf = Kf * m = -1.81 * 1.61 = -2.99 C

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