anonymous
  • anonymous
(15a^2b^5-25a^5b^3)/(10ab^4)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jdoe0001
  • jdoe0001
$$ \cfrac{15a^2b^5-25a^5b^3}{10ab^4}\\ \text{common factor atop} $$
jdoe0001
  • jdoe0001
from there just cancel out like-terms atop/bottom
anonymous
  • anonymous
so 15-25?

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anonymous
  • anonymous
a^7?
anonymous
  • anonymous
& b^8?
jdoe0001
  • jdoe0001
well, for the numerator, what's common for 15 and 25? see above ^|dw:1371156785765:dw|
jdoe0001
  • jdoe0001
or below rather hehe
anonymous
  • anonymous
I am so confused :/
jdoe0001
  • jdoe0001
well, common factor, means what's common for the elements, in this case "the elements" are the ones in the numerator
jdoe0001
  • jdoe0001
what's the same in the simplication above? for 15 and 25?
anonymous
  • anonymous
5
jdoe0001
  • jdoe0001
so, 5 now, let's see what's common for the literal's $$ a \times a\times a\times a\times a\\ a \times a\\ ----------------\\ b \times b\times b\times b\times b\\ b\times b\times b $$
jdoe0001
  • jdoe0001
they both have those, "a" and "b", so they're common, but different powers
anonymous
  • anonymous
So would it be: 5/ab - 10b/a^4
jdoe0001
  • jdoe0001
well, no, let's take the numerator alone common factor for $$ \cfrac{15a^2b^5-25a^5b^3}{10ab^4}\\ \text{common factor atop}\\ 15\color{blue}{aa}\color{green}{bbbbb}-25\color{blue}{aaaaa}\color{green}{bbb} $$
jdoe0001
  • jdoe0001
so, we know from the coefficients, the common factor is 5 now from "a" and "b", which is it?
anonymous
  • anonymous
7 and 9?
jdoe0001
  • jdoe0001
well, do you what a "common factor" is?
jdoe0001
  • jdoe0001
http://www.thefreedictionary.com/common+factor

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