anonymous
  • anonymous
if d/dx = (f(2x^5))=6x^5 calculate f'(x)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Loser66
  • Loser66
\[\frac{d}{dx}=(f(2x^5))=6x^5\]I don't understand, please explain
Mertsj
  • Mertsj
I don't know. Have to ask the smart people. @Phi
phi
  • phi
any other clues ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Loser66
  • Loser66
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
d/dx[ f(2x^5) ] = f ' (2x^5) * d/dx[2x^5] d/dx[ f(2x^5) ] = f ' (2x^5) * 10x^4 -------------------------------------- d/dx[ f(2x^5) ] = 6x^5 f ' (2x^5) * 10x^4 = 6x^5 f ' (2x^5) = 6x^5/10x^4 f ' (2x^5) = (3/5)x that's as far as I could get
anonymous
  • anonymous
so the answer is (3/5)x?
jim_thompson5910
  • jim_thompson5910
well no because they want f ' (x)
jim_thompson5910
  • jim_thompson5910
but not sure what the function f ' (x) could be, something seems missing, but idk
anonymous
  • anonymous
thanks
jim_thompson5910
  • jim_thompson5910
np, i would ask your teacher about it
phi
  • phi
ok, that makes sense @jim_thompson5910 how about a change of variables? f ' (2x^5) = (3/5)x let u= 2x^5 and x= (u/2)^(1/5) f'(u) = (3/5) (u/2)^(1/5) or , renaming u to x \[ f'(x)= \frac{3}{5} \sqrt[5]{\frac{x}{2}} \]
Loser66
  • Loser66
I am with phi, then

Looking for something else?

Not the answer you are looking for? Search for more explanations.