anonymous
  • anonymous
The figures indicate that the higher the orbit of a satellite, the more of the earth the satellite can "see." Let θ, s, and h be as in the figure, and assume the earth is a sphere of radius 3960 miles.
Trigonometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
please do not ask the same question twice, thank you is there a picture we can see? or a question we can solve?
anonymous
  • anonymous
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anonymous
  • anonymous
okay so for the first one let r be the radius of 3960 the angle will be theta theta = \[\cos^{-1} \frac{ r}{ r+h }\]

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anonymous
  • anonymous
so plug in 3960 for r and that is the first answer
anonymous
  • anonymous
If a) is looking for what theta of h is equal to, wouldn't I need to get h and theta on the same side?
anonymous
  • anonymous
your theta is dependent on what h is, you theta is an equation of h just like when you have y= 2x y in an equation of x
anonymous
  • anonymous
So my answer would be like cos^-1(3960/3960+h)?
anonymous
  • anonymous
yes, for the first question because cos(theta) = adjacent/hypotenuse adjacent = radius hypotenuse = radius + h
anonymous
  • anonymous
Okay, now part b) Thank you btw
anonymous
  • anonymous
s is an arc length the equation for arc length or a circle is radius * degree well the degree is 2*theta so s = radius * 2 * theta
anonymous
  • anonymous
(theta being in radians)
anonymous
  • anonymous
I don't follow, I'm sorry. My professor has not taught arc length.
anonymous
  • anonymous
oh, well that is how you would solve s in terms of theta :P
anonymous
  • anonymous
Okay so it would be like.. 3960*theta?
anonymous
  • anonymous
*2
anonymous
  • anonymous
so 7920*theta
anonymous
  • anonymous
"Easy" enough now for part C)
anonymous
  • anonymous
well we already solved for theta, so plug in your first answer in part A in for theta in part B
anonymous
  • anonymous
Like 7920(cos^-1(3960/3960+h))
anonymous
  • anonymous
yep
anonymous
  • anonymous
Then part d plug 100 in for h?
anonymous
  • anonymous
yeah that seems correct
anonymous
  • anonymous
Then for e... Set s equal to 3000 and solve for h?
anonymous
  • anonymous
exactly!
anonymous
  • anonymous
How would I do that with the inverse.. I haven't solved equations with an inverse yet either
anonymous
  • anonymous
you use a calculator if you're trying to find an exact answer. i'm assuming you haven't learned Taylor Series yet
anonymous
  • anonymous
No, I have not heard of It:( Also, on part d I used my calculator and got 100924 and it was apparently wrong
anonymous
  • anonymous
With decimals but that was it rounded
anonymous
  • anonymous
it's kind of silly if they expect you to get exact answers for these questions haha
anonymous
  • anonymous
were the other questions correct?
anonymous
  • anonymous
Yes!
anonymous
  • anonymous
well that's good at least :P
anonymous
  • anonymous
are you using webassign?
anonymous
  • anonymous
Yes -_-
anonymous
  • anonymous
How would I get grid of the inverse cosines in part d I know enough algebra to solve but I'm not sure what to do with the inverse
anonymous
  • anonymous
\[x = \cos^{-1} (4) ---> \cos{x} = 4\]

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