anonymous
  • anonymous
Can I do this? a² = b² + c² 13² = 12 ² + c² c² = 13² - 12² c = sqtr(13 - 12) c = sqrt(1) c = 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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zzr0ck3r
  • zzr0ck3r
sqrt(1) = +-1
jim_thompson5910
  • jim_thompson5910
are you trying to find the missing leg given a leg of 12 and a hypotenuse of 13?
zzr0ck3r
  • zzr0ck3r
and you cant do what you did with the sqrt

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zzr0ck3r
  • zzr0ck3r
c² = 13² - 12² c = sqtr(13^2 - 12^2)
jim_thompson5910
  • jim_thompson5910
if so, then a^2 + b^2 = c^2 12^2 + b^2 = 13^2 solve for b
zzr0ck3r
  • zzr0ck3r
\[c^{2} = a^{2} + b^{2}\] then \[c = \sqrt(a^{2}+b^{2}\]
anonymous
  • anonymous
Ok. I got. Thank you all.

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