anonymous
  • anonymous
Write the equation of the line that is tangent to the circle (x – 2)2 + (y – 4)2 = 289, at the point (-15, 4). a. y=4 b. x=-15 c. x=4 d. y=-15
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
not 100% sure, but I'm guessing you're not familiar with calculus right?
jim_thompson5910
  • jim_thompson5910
especially the concept of derivatives
anonymous
  • anonymous
No. Is that calculus?

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jim_thompson5910
  • jim_thompson5910
yes, seems odd how they can ask you this question when you should know about derivatives luckily there's a shortcut
jim_thompson5910
  • jim_thompson5910
the center is (2,4) the point on the circle is (-15, 4) so the slope of the line through these two points is m = (y2-y1)/(x2-x1) m = (4-4)/(-15-2) m = 0/(-17) m = 0
jim_thompson5910
  • jim_thompson5910
so this means that the line connecting the center to this point is a horizontal line
anonymous
  • anonymous
okay.
jim_thompson5910
  • jim_thompson5910
this must mean that the tangent line is a vertical line (because it makes a right angle with the radius at this point)
jim_thompson5910
  • jim_thompson5910
the x coordinate of the point (-15, 4) is x = -15 so the equation of the vertical line is x = -15
jim_thompson5910
  • jim_thompson5910
if something isn't clicking, drawing it out may help
anonymous
  • anonymous
Your a life saver. Thank you for all that. And that's a good idea.
jim_thompson5910
  • jim_thompson5910
glad to be of help

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