anonymous
  • anonymous
http://www.sketchtoy.com/38665436 @johnweldon1993
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
johnweldon1993
  • johnweldon1993
@zairhenrique if you want to jump in go right ahead I'm working it out lol
anonymous
  • anonymous
What's the question rs? Factoring ?
anonymous
  • anonymous
Factoring, yes.

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johnweldon1993
  • johnweldon1993
I mean I know the answer but how to explain it is annoying lol...so please...and yes factoringg
anonymous
  • anonymous
I got that.
johnweldon1993
  • johnweldon1993
Okay well basically....you have 2 variables...'a' and 'b' (a b) (a b) what 2 numbers add to get 12 and multiply to get 27
anonymous
  • anonymous
9 and 3?
anonymous
  • anonymous
\[a²+12ab+27b² = a²+12ab +36b² - 9b²\]\[a²+12ab+36b²-9b²=(a+6b)²-9b²\]\[(a+6b)²-9b²=(a+6b+3b)(a+6b-3b)=(a+9b)(a+3b)\]
johnweldon1993
  • johnweldon1993
Perfect...so use 9 and use 3 for your coefficients of 'b' (a + 9b)(a + 3b) I wish I could explain it more... lol
anonymous
  • anonymous
That's it:?
anonymous
  • anonymous
Yep.
johnweldon1993
  • johnweldon1993
That would be it lol
anonymous
  • anonymous
Just a trick, if you don't how to factor something like that, just try to solve it for one variable, just for example, solving it for a. \[a²+12b*a +27b²\] \[a=\frac{ -12b \pm \sqrt{(12b)²-4*27b²} }{ 2 }=\frac{ -12b \pm \sqrt{144b²-108b²} }{ 2 }\]\[a=\frac{ -12b \pm \sqrt{36b²} }{ 2 }=\frac{ -12b \pm 6b }{ 2 }=-6b \pm3b\] \[a=-6b+3b=-3b \iff a=-6b-3b=-9b\] So, if the roots are -3b and -9b, the equation is:\[(a-(-3b)(a-(-9b)=(a+3b)(a+9b)\]It's a hard and long way to do that, but, it's a way when you are in troubles haha

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