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 one year ago
Can someone help me finish this derivative, using the first principle rule. [picture attached]
 one year ago
Can someone help me finish this derivative, using the first principle rule. [picture attached]

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burhan101
 one year ago
Best ResponseYou've already chosen the best response.0dw:1371172930181:dw

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0\[f(t) = \frac{2t}{t+3}\]\[f'(t) = \lim_{h \rightarrow 0}\frac{f(t+h)f(t)}{h}\] \[f(t+h) =\frac{2(t+h)}{(t+h)+3}\] Does that help?

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0is what i have done so far right ? (there's an attachment)

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1\[\lim_{h>0}\frac{1}{h}*[\frac{6h6t2ht2t^2}{(t+3)(t+h+3)}+\frac{6t+2ht+2t^2}{(t+3)(t+h+3)}]\] is what you get after a bit of the algebraic dust settles...

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0that's exactly what im getting but i'm not understanding why my answer key shows \[\frac{ 5t2 }{ 2(5t1)^{\frac{ 3 }{ 2 }} }\]

Callisto
 one year ago
Best ResponseYou've already chosen the best response.0Double check the answer key?

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0I have, maybe it's just wrong :S

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1That's the right answer, if the problem is to find the derivative of \[\frac{t}{\sqrt{5t1}}\]
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