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anonymous
 3 years ago
Can someone help me finish this derivative, using the first principle rule. [picture attached]
anonymous
 3 years ago
Can someone help me finish this derivative, using the first principle rule. [picture attached]

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1371172930181:dw

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(t) = \frac{2t}{t+3}\]\[f'(t) = \lim_{h \rightarrow 0}\frac{f(t+h)f(t)}{h}\] \[f(t+h) =\frac{2(t+h)}{(t+h)+3}\] Does that help?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is what i have done so far right ? (there's an attachment)

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{h>0}\frac{1}{h}*[\frac{6h6t2ht2t^2}{(t+3)(t+h+3)}+\frac{6t+2ht+2t^2}{(t+3)(t+h+3)}]\] is what you get after a bit of the algebraic dust settles...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's exactly what im getting but i'm not understanding why my answer key shows \[\frac{ 5t2 }{ 2(5t1)^{\frac{ 3 }{ 2 }} }\]

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0Double check the answer key?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have, maybe it's just wrong :S

whpalmer4
 3 years ago
Best ResponseYou've already chosen the best response.1That's the right answer, if the problem is to find the derivative of \[\frac{t}{\sqrt{5t1}}\]
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