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burhan101
Group Title
Can someone help me finish this derivative, using the first principle rule. [picture attached]
 one year ago
 one year ago
burhan101 Group Title
Can someone help me finish this derivative, using the first principle rule. [picture attached]
 one year ago
 one year ago

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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1371172930181:dw
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
it's wrong btw
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
\[f(t) = \frac{2t}{t+3}\]\[f'(t) = \lim_{h \rightarrow 0}\frac{f(t+h)f(t)}{h}\] \[f(t+h) =\frac{2(t+h)}{(t+h)+3}\] Does that help?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
is what i have done so far right ? (there's an attachment)
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
\[\lim_{h>0}\frac{1}{h}*[\frac{6h6t2ht2t^2}{(t+3)(t+h+3)}+\frac{6t+2ht+2t^2}{(t+3)(t+h+3)}]\] is what you get after a bit of the algebraic dust settles...
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
that's exactly what im getting but i'm not understanding why my answer key shows \[\frac{ 5t2 }{ 2(5t1)^{\frac{ 3 }{ 2 }} }\]
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
Double check the answer key?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
I have, maybe it's just wrong :S
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
That's the right answer, if the problem is to find the derivative of \[\frac{t}{\sqrt{5t1}}\]
 one year ago
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