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burhan101

  • one year ago

Can someone help me finish this derivative, using the first principle rule. [picture attached]

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  1. burhan101
    • one year ago
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  2. burhan101
    • one year ago
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    |dw:1371172930181:dw|

  3. burhan101
    • one year ago
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    it's wrong btw

  4. Callisto
    • one year ago
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    \[f(t) = \frac{-2t}{t+3}\]\[f'(t) = \lim_{h \rightarrow 0}\frac{f(t+h)-f(t)}{h}\] \[f(t+h) =\frac{-2(t+h)}{(t+h)+3}\] Does that help?

  5. burhan101
    • one year ago
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    is what i have done so far right ? (there's an attachment)

  6. whpalmer4
    • one year ago
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    \[\lim_{h->0}\frac{1}{h}*[\frac{-6h-6t-2ht-2t^2}{(t+3)(t+h+3)}+\frac{6t+2ht+2t^2}{(t+3)(t+h+3)}]\] is what you get after a bit of the algebraic dust settles...

  7. burhan101
    • one year ago
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    that's exactly what im getting but i'm not understanding why my answer key shows \[\frac{ 5t-2 }{ 2(5t-1)^{\frac{ 3 }{ 2 }} }\]

  8. Callisto
    • one year ago
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    Double check the answer key?

  9. burhan101
    • one year ago
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    I have, maybe it's just wrong :S

  10. whpalmer4
    • one year ago
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    That's the right answer, if the problem is to find the derivative of \[\frac{t}{\sqrt{5t-1}}\]

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