## dimpledimpu100 one year ago show that time of ascent is equal to time of descent

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1. Vincent-Lyon.Fr

Use energy at a given height to prove that speed is the same on the way up and on the way down.

2. vikasandy

Initially the body is thrown vertically so,$V=u+at$ the final velocity is Zero as it reaches the max. height So,$t=u/g$ now the body has reached the max. height.. now the body acts as a freely falling body....$T=\sqrt{2h/g}$ from $v ^{2}-u ^{2}=2as$$H=u ^{2}/2g$ substituting the above in 'T' we get..$\sqrt{2/g*u ^{2}/2g}$ solving that.... we get$\sqrt{u ^{2}/g2}$ So$T=U/g$....... so time of ascent is equal to time of descent..