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VincentLyon.Fr
 one year ago
Best ResponseYou've already chosen the best response.0Use energy at a given height to prove that speed is the same on the way up and on the way down.

vikasandy
 one year ago
Best ResponseYou've already chosen the best response.1Initially the body is thrown vertically so,\[V=u+at\] the final velocity is Zero as it reaches the max. height So,\[t=u/g\] now the body has reached the max. height.. now the body acts as a freely falling body....\[T=\sqrt{2h/g}\] from \[v ^{2}u ^{2}=2as\]\[H=u ^{2}/2g\] substituting the above in 'T' we get..\[\sqrt{2/g*u ^{2}/2g}\] solving that.... we get\[\sqrt{u ^{2}/g2}\] So\[T=U/g\]....... so time of ascent is equal to time of descent..
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