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VincentLyon.FrBest ResponseYou've already chosen the best response.0
Use energy at a given height to prove that speed is the same on the way up and on the way down.
 10 months ago

vikasandyBest ResponseYou've already chosen the best response.1
Initially the body is thrown vertically so,\[V=u+at\] the final velocity is Zero as it reaches the max. height So,\[t=u/g\] now the body has reached the max. height.. now the body acts as a freely falling body....\[T=\sqrt{2h/g}\] from \[v ^{2}u ^{2}=2as\]\[H=u ^{2}/2g\] substituting the above in 'T' we get..\[\sqrt{2/g*u ^{2}/2g}\] solving that.... we get\[\sqrt{u ^{2}/g2}\] So\[T=U/g\]....... so time of ascent is equal to time of descent..
 6 months ago
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