A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
show that time of ascent is equal to time of descent
anonymous
 3 years ago
show that time of ascent is equal to time of descent

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Use energy at a given height to prove that speed is the same on the way up and on the way down.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Initially the body is thrown vertically so,\[V=u+at\] the final velocity is Zero as it reaches the max. height So,\[t=u/g\] now the body has reached the max. height.. now the body acts as a freely falling body....\[T=\sqrt{2h/g}\] from \[v ^{2}u ^{2}=2as\]\[H=u ^{2}/2g\] substituting the above in 'T' we get..\[\sqrt{2/g*u ^{2}/2g}\] solving that.... we get\[\sqrt{u ^{2}/g2}\] So\[T=U/g\]....... so time of ascent is equal to time of descent..
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.