anonymous
  • anonymous
I=∫∫xydxdy. x^2+y^2≤7
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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experimentX
  • experimentX
\[ \int_{-\sqrt 7 }^{\sqrt 7} \int_{-\sqrt{7 - x^2}}^{\sqrt{7 - x^2}} xy \; dy dx\]
experimentX
  • experimentX
In polar coordinates \[ \int_0^\sqrt7 \int_0^{2 \pi} r^3\sin \theta \cos \theta d\theta dr\]
dan815
  • dan815
yes

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dan815
  • dan815
let her work it out she needs some practice setting up integrals
anonymous
  • anonymous
you scared me. i tried to do it on my on and i jumped straight to polar. why r^3? probably a stupid question but i need to understand it not just find out the answer
dan815
  • dan815
because rdrdtheta = polar and x = rcostheta y=rsintheta
dan815
  • dan815
|dw:1371222735883:dw|
anonymous
  • anonymous
ohh i got it. i didn't put r before dr dtheta and i got a really weird result. thanks
dan815
  • dan815
here try to do this problem |dw:1371222811367:dw|
dan815
  • dan815
i want you to integrate over that area!!! but the catch is do it in polar
Zarkon
  • Zarkon
by the symmetry of the problem one should know the answer
dan815
  • dan815
tell me what ur thinking about it so far
dan815
  • dan815
when u wanna do polar u first gotta think okay so i need everything in R and thetas
anonymous
  • anonymous
i've done this last year and strenght of materials. hold on a sec let me see if a get it right
dan815
  • dan815
ok
anonymous
  • anonymous
i've got 8/3. i think a have a mistake somewhere. i'll do it again
experimentX
  • experimentX
sin(theta) cos(theta) = 1/2 sin(2 theta) if you integrate sin theta 0 to 2Pi, you should get zero.
dan815
  • dan815
i dont want answer i just want to see how ur setting up the polar integration sry shudda made that clear :)
dan815
  • dan815
|dw:1371223972276:dw|
anonymous
  • anonymous
ok i give up. i'm having problems with the boudaries at every problem. i don't get them right :(((

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