anonymous
  • anonymous
find the inverse of y=2x^2-5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Notice that for the inverse, the x and y switch their places. So first replace y with x and x with y, then re-arrange and solve for y. 1) Switch x and y:\[\bf y=2x^2-5 \rightarrow x = 2y^2-5\]2) Solve for y:\[\bf x=2y^2-5 \rightarrow \frac{ x+5 }{ 2 }=y^2 \implies y^2 = \frac{x+5 }{ 2 }\] @selenamalter
anonymous
  • anonymous
Alternatively, you could take the square root of both sides but then since square is always positive, you will need to have it as:\[\bf y=\pm \sqrt{\frac{ x+5 }{ 2 }}\]The "plus-minus" is necessary since we need two parts, one above the x-axis and one below the axis. Leaving the square root without the "pm" sign will only result in the positive part. To get rid of this confusion, it's best to leave the function in terms of "y^2" as I did in the previous reply since you don't have to deal with the "pm" sign. @selenamalter

Looking for something else?

Not the answer you are looking for? Search for more explanations.