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the first problem you have x 7x - 8 ------ + -------- 8x 8x
whta is the common denominator
ok then you have x + 7x - 8 ---------- 8x
ok so my answer would be |dw:1371232193752:dw|
no you can do that
not do that
then you have 8x - 8 ------ 8x
you can take out the 8 8(x-1) ------ 8x
now you can cancel the 8 and you have x - 1 ----- x
which is the same as 1 - 1/x
ohhh ok wb #2
what would i do ther because they dont have common denominators
the second problem you have 4 1 ----- + ------- x-7 x-3
What is the common denominator ??
no, actually you have to take the hold thing so the common denominator would be (x-7)(x-3)
so now what you do is 4 (x-3) + 1 (x-7) --------------- (x-3)(x-7)
ok then u would have |dw:1371232713526:dw|
no, you need to first multiply 4(x-3) and then 1(x-7)
then you have 4x - 12 + x - 7 -------------- (x-3)(x-7)
now combine like terms
would that be the answer?
invettef365 u still there?
yes that is correct
ok ty hate to do this but i only got one more problem on my HW could u help me out with it?
no actually it is 5x - 19 -------- (x-3)(x-7)
ty simplify (x+1/x^2)+(3/4x)
ok, you have x + 1 3 ------- + -------- x^2 4x
what is the common denominator??
actually it is 4x^2
:( i hate fractions
because you can divide as follows: 4x^2 4x^2 ---- = x and ------ = 4x 4x x
sorry I meant 4x^2 ----- = 4 x^2
then you have 4(x+1) + 3(x) ------------- 4x^2
do you understand how I got there?
yea sort of
since 4x^2/x^2 = 4 I multiply 4 (x+1) and since 4x^2/4x = x I multiply 3(x)
ok i got it
know multiply 4(x+1) and 3(x) what do you get
right then you have 7x +4 ------ 4x^2
ty so much invette