anonymous
  • anonymous
A survey of high school juniors found that 78% of students plan on attending college. If you pick three students at random, what is the probability that at least two plan on attending college? Round to the nearest percent. a) 53% b) 12% c) 40% d) 88%
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Please help!
whpalmer4
  • whpalmer4
Well, for any 1 student you might select, what is the probability that they plan to attend college?
anonymous
  • anonymous
50/50?

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More answers

whpalmer4
  • whpalmer4
How do you get that?
anonymous
  • anonymous
well, there's only two choices and either one is a possibility.
anonymous
  • anonymous
"at least two" means not none, not one compute \(P(x=0)\) and \(P(x=1)\) and subtract the result from 1
anonymous
  • anonymous
oh i see, there are only three students so you could also compute \(P(x=2)\) and \(P(x=3)\) and add them
anonymous
  • anonymous
binomial distribution \[P(x=2)=3\times (.78)^2\times (.22)\] and \[P(x=3)=(.78)^3\] if it is not clear where these numbers come from, let me know
anonymous
  • anonymous
No, I understand. This is how I solved the equation but I got it wrong some how... \[3C2 (.78)^2 * (.22)^1\]
anonymous
  • anonymous
Should I not have the 1 above .22?
anonymous
  • anonymous
that is \(P(x=2)\) yes and \(_3C_2=3\)
anonymous
  • anonymous
did you add \((.78)^3\) to your result?
anonymous
  • anonymous
No.
anonymous
  • anonymous
it says "at least two" so it means "two or three" you have to add them
anonymous
  • anonymous
ah ok
anonymous
  • anonymous
So the answer's d-) 88% right?
anonymous
  • anonymous
@satellite73 ?
anonymous
  • anonymous
i don't know, i didn't compute it hold on i will check
anonymous
  • anonymous
Thanks :)
whpalmer4
  • whpalmer4
I get 0.876096 for that result..so yeah.
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=3*%28.78%29^2*.22%2B.78^3
anonymous
  • anonymous
I did too I just rounded. :)
anonymous
  • anonymous
yeah, looks good
anonymous
  • anonymous
Thanks so much for the help!

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