anonymous
  • anonymous
could someone please walk me through this problem practice problem: 5. Which of the following is equivalent to 3a + 4b – (–6a – 3b) ? A. 16ab B. –3a +b C. –3a + 7b D. 9a +b E. 9a + 7b
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
First resolve your parentheses. Do you understand how to get rid of them?
anonymous
  • anonymous
no
anonymous
  • anonymous
9a+7b is your answer

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anonymous
  • anonymous
First rewrite the equation: 3a+4b+6a+3b Now combine like terms 9a+7b Which is answer E.
anonymous
  • anonymous
You can look at "3a + 4b – (–6a – 3b)" this way: 3a +4b –1(–6a –3b)
anonymous
  • anonymous
i havent taken a math class in 5 years and today i am studding for a placement test i seem to have forgotten alot
anonymous
  • anonymous
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anonymous
  • anonymous
not that i know what to do with that
anonymous
  • anonymous
Well, one thing you should always remember is "PEMDAS", which is the "order of operations" in a mathematical sequence. (P)arentheses are resolved first, followed by (E)xponents and roots (M)ultiplication and (D)ivision (A)ddition and (S)ubtraction
anonymous
  • anonymous
Yes, EXACTLY like that! Very good!
anonymous
  • anonymous
6a=3b? is that the parentheses
anonymous
  • anonymous
6a+3b***
anonymous
  • anonymous
then add everything like doll said
anonymous
  • anonymous
to get 9a + 7b
anonymous
  • anonymous
The items in parentheses are seen as their own entity, which is where the "1" comes from. Since you're subtracting the entity, then the "1" is a "-1". So -1 * (-6a -3b) is: -1 * -6a = +6a -1 * -3b = +3b And that's how you get rid of the parentheses. 3a +4b –(–6a –3b) Becomes 3a +4b –1(–6a –3b) which is 3a +4b (+6a +3b) which is 3a +4b +6a +3b Now you can combine the "a" terms and the "b" terms.
anonymous
  • anonymous
what is the sum of the polynomial \[3a ^{2}b+2a ^{2}b ^{2} and -ab ^{2}+a ^{2}b ^{2}?\] does ab always stay together?
anonymous
  • anonymous
I'm not real strong here... But it looks like the problem is: 3a^2b +2a^2b^2 -ab^2 +a^2b^2 So it looks like you can resolve the "+2a^2b^2 +a^2b^2" part, and then the other "3a^2b -ab^2" remains unchanged As I said, I'm not strong here at all.

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