anonymous
  • anonymous
solve 3(5t+4)<13t-10
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
I got t<-11 is that right?
jim_thompson5910
  • jim_thompson5910
you are correct
anonymous
  • anonymous
ok do I need to write it differently or just leave it like that

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jim_thompson5910
  • jim_thompson5910
you could leave it like that or write it in set builder notation or interval notation
jim_thompson5910
  • jim_thompson5910
depends on how your book wants the answer
anonymous
  • anonymous
I think I'm supposed to use interval notation
jim_thompson5910
  • jim_thompson5910
ok what do you get when you convert over
anonymous
  • anonymous
uummm you write equal to all real number less than -11?
jim_thompson5910
  • jim_thompson5910
you want to describe the interval of all numbers less than -11
jim_thompson5910
  • jim_thompson5910
so if you wanted to described the interval from 5 to 23 (not including either endpoint), then you would write: (5, 23)
anonymous
  • anonymous
(0,-11) ?
jim_thompson5910
  • jim_thompson5910
0 is larger than -11 so that makes no sense
anonymous
  • anonymous
I dont know then because I know its less than -11 but I dont have a number that its greater than...so do I just leave it open ended?
jim_thompson5910
  • jim_thompson5910
how would I describe the interval of numbers larger than 5
jim_thompson5910
  • jim_thompson5910
you would do something like 5, 6, 7, 8, ... so (5, 7) is one interval...but leaves out numbers like 8, 9, 10, etc (5, 23) is another interval, but numbers like 30, 40, 50 are left out this interval is open ended because there are infinitely many numbers that are greater than 5 so you would write \[\large\left(5,\infty \right )\]
jim_thompson5910
  • jim_thompson5910
does that example help?
anonymous
  • anonymous
so \[(-11,-\infty)\]
jim_thompson5910
  • jim_thompson5910
close, but the negative infinity is always on the left because it's always smaller
jim_thompson5910
  • jim_thompson5910
in my example, infinity is on the right since it's always larger
anonymous
  • anonymous
ok \[(-\infty,-11)\]
jim_thompson5910
  • jim_thompson5910
good, remember you're reading this from left to right (smaller to bigger) so that's why (0, -11) doesn't make any sense...however (-11, 0) does make sense
anonymous
  • anonymous
but that doesn't work in my case because t is less than -11
jim_thompson5910
  • jim_thompson5910
don't worry about (0, -11) and (-11, 0), they are just examples of what is good and bad notation for interval notation
anonymous
  • anonymous
ok thanks
jim_thompson5910
  • jim_thompson5910
the answer is \[\large\left(-\infty,-11 \right )\] and you already got that
jim_thompson5910
  • jim_thompson5910
np

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