anonymous
  • anonymous
question below:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1371248333185:dw|
AndrewKaiser333
  • AndrewKaiser333
that is where you end up at
AndrewKaiser333
  • AndrewKaiser333
\[\frac{ \sqrt{3}-\sqrt{3} }{ h }\]

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AndrewKaiser333
  • AndrewKaiser333
k?
AndrewKaiser333
  • AndrewKaiser333
which equals
AndrewKaiser333
  • AndrewKaiser333
\[\frac{ 3-3 }{ h }\]
AndrewKaiser333
  • AndrewKaiser333
then it would be \[\frac{ 0 }{ 6 }\]
AndrewKaiser333
  • AndrewKaiser333
but that don't make sense
anonymous
  • anonymous
the given answer is actually \\[1\div2\sqrt{3}\]
AndrewKaiser333
  • AndrewKaiser333
or did i answer it already before i kept going on
AndrewKaiser333
  • AndrewKaiser333
which equals 3.47
AndrewKaiser333
  • AndrewKaiser333
then
AndrewKaiser333
  • AndrewKaiser333
my way i guess was old school of doing it or i learned it wrong sorry but the answer would then be 3.47 if you go the way they shoow
AndrewKaiser333
  • AndrewKaiser333
sorry i messed you up i am getting confused
anonymous
  • anonymous
lol its fine
AndrewKaiser333
  • AndrewKaiser333
i will let someone help you other than me i think i am just wasting your time trying to help when obviously i am screwing my self up
anonymous
  • anonymous
alright, lol thanks for trying, really appreciate it!
AndrewKaiser333
  • AndrewKaiser333
hey please help cutie @Cutie<3
AndrewKaiser333
  • AndrewKaiser333
@Cutie<3
anonymous
  • anonymous
Haha(: I'm really sorry, but math isn't my best subject:P Hope you can find the right help!
anonymous
  • anonymous
its okay lol thanks!
anonymous
  • anonymous
\[\lim_{h\to 0}\frac{\sqrt{3+h}-\sqrt{3}}{h}\] multiply top and bottom by \(\sqrt{3+h}+\sqrt{3}\)
anonymous
  • anonymous
you get \[\frac{\sqrt{3+h}-\sqrt{3}}{h}\times \frac{\sqrt{3+h}+\sqrt{3}}{\sqrt{3+h}+\sqrt{3}}\] \[=\frac{3+h-3}{h(\sqrt{3+h}+\sqrt{3})}\]
anonymous
  • anonymous
ohh yes i remember that method!!
anonymous
  • anonymous
cancel the \(h\) top and bottom and you get \[\frac{1}{\sqrt{3+h}+\sqrt{3}}\]
anonymous
  • anonymous
the take the limit by replacing \(h\) by \(0\)
anonymous
  • anonymous
thanks you so much!!

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