anonymous
  • anonymous
(-10x^3+30x-20) divided by (-5x+5)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I think you should separate the problem into smaller fractions.
Luigi0210
  • Luigi0210
|dw:1371261533166:dw|
anonymous
  • anonymous
i don't understand what you did there but ok

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Luigi0210
  • Luigi0210
actually that wouldn't work i think..
Luigi0210
  • Luigi0210
@Jhannybean
Jhannybean
  • Jhannybean
i'm drawing it out using Sketch Toy..
Luigi0210
  • Luigi0210
haha sketch toy
Luigi0210
  • Luigi0210
darn guess it's back to long division
anonymous
  • anonymous
as i said before break it up into smaller parts so you could solve it easier
Jhannybean
  • Jhannybean
http://www.sketchtoy.com/39029723
Luigi0210
  • Luigi0210
:l
anonymous
  • anonymous
you did good lol
Jhannybean
  • Jhannybean
Is there a negative infront of the "2x^2"?Hmm.
Luigi0210
  • Luigi0210
forget it mine is awful.. it's trash.. it's not worth looking at :(
Luigi0210
  • Luigi0210
haha
Luigi0210
  • Luigi0210
another reason for me to hang up the towel
anonymous
  • anonymous
$$-10x^3+30x-20=-10(x^3-3x+2)\\-5x+5=-5(x-1)\\\frac{-10x^3+30x-20}{-5x+5}=\frac{-10(x^3-3x+2)}{-5(x-1)}=2\frac{x^3-3x+2}{x-1}$$Now, let's try to rewrite \(x^3-3x+2\) in a "nice" form for division:$$\begin{align*}x^3-3x+2&=x(x^2-3)+2\\&=(x-1+1)(x^2-3)+2\\&=(x-1)(x^2-3)+x^2-3+2\\&=(x-1)(x^2-3)+x^2-1\\&=(x-1)(x^2-3)+(x-1)(x+1)\\&=(x-1)(x^2-3+x+1)\\&=(x-1)(x^2+x-2)\\\frac{x^3-3x+2}{x-1}&=\frac{(x-1)(x^2+x-2)}{x-1}\\&=x^2+x-2\\2\frac{x^3-3x+2}{x-1}&=2x^3+2x-4\end{align*}$$
jim_thompson5910
  • jim_thompson5910
see attached for the long division
1 Attachment

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