Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = -2.
Stacey Warren - Expert brainly.com
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@jhannybean @goformit100 What does a directrix of y=-2 mean to you?
@jhannybean @goformit100 Perhaps a sketch showing both your proposed parabola and y = -2 would be informative :-)
I mislabeled the parabola — though it says \(y^2=x\) it is a graph of \(y^2=8x\)
What do you use to show your graphs btw?
Does \(y=-2\) look like the directrix of that parabola? :-)
Oh i see...it would have been x=-2.... Hmm.
I'll delete my work. lol.
Why not post a corrected version?
http://www.sketchtoy.com/39052824 he distance from the focus to the vertex is equal to the distance from the directrix to the vertex. The distance is labeled as "p" Use the form \[\large (x-h)^2 = 4p(y-k)\] since this parabola is opening up and down.
vertex= (0,0) ,p = 2 (distance of center from focus and center to directrix) \[\large (x-0)^2 = 4(2)(y-0)\]\[\large x^2 = 8y\]
And your final graph will look something like http://www.sketchtoy.com/39073173