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burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge f'(x)=1+cosx\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4now plug in x=pi into the xvalue

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.1yeah.. now put in x=pi.. that would give you the slope.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4\[\large f'(\pi )= 1 + \cos(\pi) = 0\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4because cos(pi) = 1.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0y=180 would be the equation ?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. \[\large y=f(\pi) = \pi + \sin(\pi)\] what is your yvalue?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4_ y = pi. now we have m =0, y = pi, x= pi. \[yy_{1}= m(xx_{1})\]\[y\pi = 0(x\pi)\]\[y=\pi\]

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0No .. we can substitute pi for 180 @Jhannybean

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4You get the same thing :P
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