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anonymous
 2 years ago
Determine the equation of the tangent to f(x)=x+sinx at x= pi
anonymous
 2 years ago
Determine the equation of the tangent to f(x)=x+sinx at x= pi

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\huge f'(x)=1+cosx\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0now plug in x=pi into the xvalue

yrelhan4
 2 years ago
Best ResponseYou've already chosen the best response.1yeah.. now put in x=pi.. that would give you the slope.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large f'(\pi )= 1 + \cos(\pi) = 0\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0because cos(pi) = 1.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0y=180 would be the equation ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. \[\large y=f(\pi) = \pi + \sin(\pi)\] what is your yvalue?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0_ y = pi. now we have m =0, y = pi, x= pi. \[yy_{1}= m(xx_{1})\]\[y\pi = 0(x\pi)\]\[y=\pi\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0No .. we can substitute pi for 180 @Jhannybean

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0You get the same thing :P
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