## anonymous 2 years ago Determine the equation of the tangent to f(x)=x+sinx at x= pi

1. anonymous

$\huge f'(x)=1+cosx$

2. anonymous

f'(x) = m

3. anonymous

now plug in x=pi into the x-value

4. yrelhan4

yeah.. now put in x=pi.. that would give you the slope.

5. anonymous

y= 180

6. anonymous

$\large f'(\pi )= 1 + \cos(\pi) = 0$

7. anonymous

m=0

8. anonymous

because cos(pi) = -1.

9. yrelhan4

you won, madame. :)

10. anonymous

y=180 would be the equation ?

11. anonymous

so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. $\large y=f(\pi) = \pi + \sin(\pi)$ what is your y-value?

12. anonymous

y=180

13. anonymous

-_- y = pi. now we have m =0, y = pi, x= pi. $y-y_{1}= m(x-x_{1})$$y-\pi = 0(x-\pi)$$y=\pi$

14. anonymous

No .. we can substitute pi for 180 @Jhannybean

15. anonymous

You get the same thing :P

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