Determine the equation of the tangent to f(x)=x+sinx at x= pi

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Determine the equation of the tangent to f(x)=x+sinx at x= pi

Mathematics
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\[\huge f'(x)=1+cosx\]
f'(x) = m
now plug in x=pi into the x-value

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Other answers:

yeah.. now put in x=pi.. that would give you the slope.
y= 180
\[\large f'(\pi )= 1 + \cos(\pi) = 0\]
m=0
because cos(pi) = -1.
you won, madame. :)
y=180 would be the equation ?
so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. \[\large y=f(\pi) = \pi + \sin(\pi)\] what is your y-value?
y=180
-_- y = pi. now we have m =0, y = pi, x= pi. \[y-y_{1}= m(x-x_{1})\]\[y-\pi = 0(x-\pi)\]\[y=\pi\]
No .. we can substitute pi for 180 @Jhannybean
You get the same thing :P

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