A community for students.
Here's the question you clicked on:
 0 viewing
burhan101
 one year ago
Determine the equation of the tangent to f(x)=x+sinx at x= pi
burhan101
 one year ago
Determine the equation of the tangent to f(x)=x+sinx at x= pi

This Question is Closed

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge f'(x)=1+cosx\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4now plug in x=pi into the xvalue

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.1yeah.. now put in x=pi.. that would give you the slope.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4\[\large f'(\pi )= 1 + \cos(\pi) = 0\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4because cos(pi) = 1.

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0y=180 would be the equation ?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. \[\large y=f(\pi) = \pi + \sin(\pi)\] what is your yvalue?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4_ y = pi. now we have m =0, y = pi, x= pi. \[yy_{1}= m(xx_{1})\]\[y\pi = 0(x\pi)\]\[y=\pi\]

burhan101
 one year ago
Best ResponseYou've already chosen the best response.0No .. we can substitute pi for 180 @Jhannybean

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.4You get the same thing :P
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.