burhan101
Determine the equation of the tangent to f(x)=x+sinx at x= pi
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burhan101
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\[\huge f'(x)=1+cosx\]
burhan101
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f'(x) = m
Jhannybean
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now plug in x=pi into the x-value
yrelhan4
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yeah.. now put in x=pi.. that would give you the slope.
burhan101
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y= 180
Jhannybean
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\[\large f'(\pi )= 1 + \cos(\pi) = 0\]
burhan101
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m=0
Jhannybean
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because cos(pi) = -1.
yrelhan4
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you won, madame. :)
burhan101
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y=180 would be the equation ?
Jhannybean
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so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into
To figure out the "y" value, plug x=pi back into original equation.
\[\large y=f(\pi) = \pi + \sin(\pi)\] what is your y-value?
burhan101
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y=180
Jhannybean
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-_- y = pi.
now we have m =0, y = pi, x= pi.
\[y-y_{1}= m(x-x_{1})\]\[y-\pi = 0(x-\pi)\]\[y=\pi\]
burhan101
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No .. we can substitute pi for 180 @Jhannybean
Jhannybean
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You get the same thing :P