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burhan101Best ResponseYou've already chosen the best response.0
\[\huge f'(x)=1+cosx\]
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.4
now plug in x=pi into the xvalue
 10 months ago

yrelhan4Best ResponseYou've already chosen the best response.1
yeah.. now put in x=pi.. that would give you the slope.
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.4
\[\large f'(\pi )= 1 + \cos(\pi) = 0\]
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.4
because cos(pi) = 1.
 10 months ago

burhan101Best ResponseYou've already chosen the best response.0
y=180 would be the equation ?
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.4
so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. \[\large y=f(\pi) = \pi + \sin(\pi)\] what is your yvalue?
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.4
_ y = pi. now we have m =0, y = pi, x= pi. \[yy_{1}= m(xx_{1})\]\[y\pi = 0(x\pi)\]\[y=\pi\]
 10 months ago

burhan101Best ResponseYou've already chosen the best response.0
No .. we can substitute pi for 180 @Jhannybean
 10 months ago

JhannybeanBest ResponseYou've already chosen the best response.4
You get the same thing :P
 10 months ago
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