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burhan101

Determine the equation of the tangent to f(x)=x+sinx at x= pi

  • 10 months ago
  • 10 months ago

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  1. burhan101
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    \[\huge f'(x)=1+cosx\]

    • 10 months ago
  2. burhan101
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    f'(x) = m

    • 10 months ago
  3. Jhannybean
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    now plug in x=pi into the x-value

    • 10 months ago
  4. yrelhan4
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    yeah.. now put in x=pi.. that would give you the slope.

    • 10 months ago
  5. burhan101
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    y= 180

    • 10 months ago
  6. Jhannybean
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    \[\large f'(\pi )= 1 + \cos(\pi) = 0\]

    • 10 months ago
  7. burhan101
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    m=0

    • 10 months ago
  8. Jhannybean
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    because cos(pi) = -1.

    • 10 months ago
  9. yrelhan4
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    you won, madame. :)

    • 10 months ago
  10. burhan101
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    y=180 would be the equation ?

    • 10 months ago
  11. Jhannybean
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    so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into To figure out the "y" value, plug x=pi back into original equation. \[\large y=f(\pi) = \pi + \sin(\pi)\] what is your y-value?

    • 10 months ago
  12. burhan101
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    y=180

    • 10 months ago
  13. Jhannybean
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    -_- y = pi. now we have m =0, y = pi, x= pi. \[y-y_{1}= m(x-x_{1})\]\[y-\pi = 0(x-\pi)\]\[y=\pi\]

    • 10 months ago
  14. burhan101
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    No .. we can substitute pi for 180 @Jhannybean

    • 10 months ago
  15. Jhannybean
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    You get the same thing :P

    • 10 months ago
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