goformit100
  • goformit100
The number of values of k, for which the system of equations (k + 1)x + 8y = 4k kx + (k + 3)y = 3k − 1 has no solution, is (1) 1 (2) 2 (3) 3 (4) infinite
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Nurali
  • Nurali
i think 2
anonymous
  • anonymous
For them to have no solution, the lines described by the equations must be parallel, i.e. $$k+1=kt\\8=(k+3)t\\4k=3kt$$How many \(k\) satisfy the above constraints for arbitrary \(t\)?
anonymous
  • anonymous
$$4k=3(k+1)\\4k=3k+3\\k=3\\t=\frac43$$... this is the only solution I can find.

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anonymous
  • anonymous
It's an overdetermined system anyways.

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