uri
  • uri
A bag contains 6 white and 8 black balls.If 4 balls are drawn.What is the probability that: a)All are black b)2 are white and 2 are black
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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terenzreignz
  • terenzreignz
Someone likes advance reading :D
dan815
  • dan815
wut do u mean
terenzreignz
  • terenzreignz
First one can actually be done without the use of combinations... but more on that later.

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More answers

terenzreignz
  • terenzreignz
Basic concept of probability, @uri ?
uri
  • uri
I don't really understand the question :D
dan815
  • dan815
|dw:1371298995534:dw|
terenzreignz
  • terenzreignz
:3 That tends to happen when you read (too far) in advance :D Anyway, the gist of probability (when it's discrete) is that you're counting the number of 'good' outcomes and dividing it by the total number of outcomes...
terenzreignz
  • terenzreignz
So, let's forget about the current question for the moment, and just say, we're trying to get the probability of drawing JUST ONE black ball, aye? :)
uri
  • uri
Everyone looking at my Ques yo!
uri
  • uri
Lol.
terenzreignz
  • terenzreignz
It's a weekend, interesting questions are hard to come by @uri :)
anonymous
  • anonymous
its a trick question. there are no balls.
uri
  • uri
@chris00 Explain me.
anonymous
  • anonymous
use magic.
uri
  • uri
@terenzreignz :(
dan815
  • dan815
terenz are u gonna answer this or shud i take over... u started something
dan815
  • dan815
i guess ill take over
dan815
  • dan815
|dw:1371299452010:dw|
dan815
  • dan815
say these 4 spots are how u draw the balls
dan815
  • dan815
|dw:1371299509605:dw|
uri
  • uri
Okay..then?
dan815
  • dan815
now after the 8/14 chance u draw black first, u have 7/13 chance to draw black
uri
  • uri
Who says? :p
dan815
  • dan815
hm, think about it like this
dan815
  • dan815
|dw:1371299586952:dw|
dan815
  • dan815
how can u arrange 5 ppl in 3 spots
uri
  • uri
Idk...on each other.
dan815
  • dan815
|dw:1371299605047:dw|
dan815
  • dan815
u have 5 choices for the first spot|dw:1371299645056:dw|
dan815
  • dan815
then u will have 4 choices because only 4 ppl are left to choose from after you pick 1 guy, then for every first guy u pick from which u have 5 guys to pick each case will have 4 different guys u can pick from on the 2nd turn
dan815
  • dan815
so 5*4 for 2 places and then 5*4*3 for 3 places
dan815
  • dan815
instead of working with whole numbers, we are working with probability numbers for your case
dan815
  • dan815
think of it like this say there is half a chance your kid will be a boy, so whats the chance both of your kids will be boys
dan815
  • dan815
|dw:1371299761321:dw|
dan815
  • dan815
on the first child you have 1/2 chance of boy, and then from there another 1/2 chance on the 2nd boy, so out of total cases, u have 1 case will give u right result
dan815
  • dan815
same way is how you do this you divide by the case that u want / the total number of cases
dan815
  • dan815
now what iff i asked this questions a bit differently
dan815
  • dan815
say there are 5 people 2 are girls and 3 are boys
dan815
  • dan815
what is the chance that you pick both boys on the first case
dan815
  • dan815
|dw:1371300012067:dw|
dan815
  • dan815
what is the chance u will pick a boy on the first turn
dan815
  • dan815
??
terenzreignz
  • terenzreignz
Sorry guys, my internet really hates me.
dan815
  • dan815
oh ok i thought u gave up on her
terenzreignz
  • terenzreignz
Me? No, I only give up on people that absolutely refuse to learn :D
uri
  • uri
And I didn't understand anything because i was offline...
uri
  • uri
I'll ask this ques again..tomorrow.

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