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goformit100
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Consider the sequence 2;3;5;6;7;8;10;::: of all positive integers that are not perfect squares. Determine the 2011th term of this sequence.
 one year ago
 one year ago
goformit100 Group Title
Consider the sequence 2;3;5;6;7;8;10;::: of all positive integers that are not perfect squares. Determine the 2011th term of this sequence.
 one year ago
 one year ago

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goformit100 Group TitleBest ResponseYou've already chosen the best response.0
@oldrin.bataku
 one year ago

oldrin.bataku Group TitleBest ResponseYou've already chosen the best response.0
Find the number of perfect squares under 2011  this is the difference between 2011 and our number.
 one year ago

oldrin.bataku Group TitleBest ResponseYou've already chosen the best response.0
Well, we know \(\sqrt{2011}\approx45\) with rounding (since \(44^2=1936\), \(45^2=2025\)). This means we have skipped \(45\) square numbers at this point, so our 2011th term is \(2011+45=2056\)
 one year ago
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