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Consider the sequence 2;3;5;6;7;8;10;::: of all positive integers that are not perfect squares. Determine the 2011th term of this sequence.
 10 months ago
 10 months ago
Consider the sequence 2;3;5;6;7;8;10;::: of all positive integers that are not perfect squares. Determine the 2011th term of this sequence.
 10 months ago
 10 months ago

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oldrin.batakuBest ResponseYou've already chosen the best response.0
Find the number of perfect squares under 2011  this is the difference between 2011 and our number.
 10 months ago

oldrin.batakuBest ResponseYou've already chosen the best response.0
Well, we know \(\sqrt{2011}\approx45\) with rounding (since \(44^2=1936\), \(45^2=2025\)). This means we have skipped \(45\) square numbers at this point, so our 2011th term is \(2011+45=2056\)
 10 months ago
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