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csimmons3

  • 2 years ago

How do you put y=0.05x^2-x+1 in general form Please help i give medals !

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  1. csimmons3
    • 2 years ago
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    Please help, i really dont get this

  2. calculusxy
    • 2 years ago
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    I am working on it.

  3. csimmons3
    • 2 years ago
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    thanks :)

  4. calculusxy
    • 2 years ago
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    I believe the answer is 0

  5. csimmons3
    • 2 years ago
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    It has to be put in general form and its equation is Y=a(x-h)^2+k

  6. calculusxy
    • 2 years ago
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    Do you know the numbers to fill the variables?

  7. csimmons3
    • 2 years ago
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    ive gotten so far: y=0.05x^2-x+1 y-1=.05x^2-x y-1+.25=.05x^2-x+.25 y-.75=.05x^2-x+.25

  8. calculusxy
    • 2 years ago
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    I don't know now except for 0

  9. csimmons3
    • 2 years ago
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    I dont think thats 0 is right

  10. calculusxy
    • 2 years ago
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    Sorry about that.

  11. sasogeek
    • 2 years ago
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    \(\large y=0.05x^{2}-x+1 \) \(\large y=0.05x^{2-x}+1 \) \(\large y=0.05x^{2-x+1} \) which one is your question?

  12. csimmons3
    • 2 years ago
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    The very first one

  13. tanjeetsarkar96
    • 2 years ago
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    y = 0.05x(x-20) + 0.01 , u want in this form?

  14. csimmons3
    • 2 years ago
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    i dont think so, the eqaution says y=a(x-h)^2+k

  15. calculusxy
    • 2 years ago
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    Is that a quadratic equation? I believe.

  16. csimmons3
    • 2 years ago
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    im not sure, it might be called that or the general form eqaution

  17. amistre64
    • 2 years ago
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    general form is: y = ax^2 + bx + c

  18. csimmons3
    • 2 years ago
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    i keep getting x=.05(x-10)-4 i think imright but im not sure

  19. amistre64
    • 2 years ago
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    y = 0.05x^2 - x + 1 , is in general form, unless theres some nitpicking rule about integer coeffs as opposed to ratioanl coeffs

  20. csimmons3
    • 2 years ago
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    my paper says its in standard form

  21. amistre64
    • 2 years ago
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    standard form appears to be:\[y=a\left(x+\frac{b}{2a}\right)^2-\left(\frac{b^2-4ac}{4a}\right)\]

  22. calculusxy
    • 2 years ago
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    I believe that you should find the sum that equals to 1 and the product that's equal to 0.05. However, both the numbers used will have to be same used in the 0.05 and 1. So it can be like (x+\-___)(x+\-_____)

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