anonymous
  • anonymous
How do you put y=0.05x^2-x+1 in general form Please help i give medals !
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Please help, i really dont get this
calculusxy
  • calculusxy
I am working on it.
anonymous
  • anonymous
thanks :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

calculusxy
  • calculusxy
I believe the answer is 0
anonymous
  • anonymous
It has to be put in general form and its equation is Y=a(x-h)^2+k
calculusxy
  • calculusxy
Do you know the numbers to fill the variables?
anonymous
  • anonymous
ive gotten so far: y=0.05x^2-x+1 y-1=.05x^2-x y-1+.25=.05x^2-x+.25 y-.75=.05x^2-x+.25
calculusxy
  • calculusxy
I don't know now except for 0
anonymous
  • anonymous
I dont think thats 0 is right
calculusxy
  • calculusxy
Sorry about that.
sasogeek
  • sasogeek
\(\large y=0.05x^{2}-x+1 \) \(\large y=0.05x^{2-x}+1 \) \(\large y=0.05x^{2-x+1} \) which one is your question?
anonymous
  • anonymous
The very first one
anonymous
  • anonymous
y = 0.05x(x-20) + 0.01 , u want in this form?
anonymous
  • anonymous
i dont think so, the eqaution says y=a(x-h)^2+k
calculusxy
  • calculusxy
Is that a quadratic equation? I believe.
anonymous
  • anonymous
im not sure, it might be called that or the general form eqaution
amistre64
  • amistre64
general form is: y = ax^2 + bx + c
anonymous
  • anonymous
i keep getting x=.05(x-10)-4 i think imright but im not sure
amistre64
  • amistre64
y = 0.05x^2 - x + 1 , is in general form, unless theres some nitpicking rule about integer coeffs as opposed to ratioanl coeffs
anonymous
  • anonymous
my paper says its in standard form
amistre64
  • amistre64
standard form appears to be:\[y=a\left(x+\frac{b}{2a}\right)^2-\left(\frac{b^2-4ac}{4a}\right)\]
calculusxy
  • calculusxy
I believe that you should find the sum that equals to 1 and the product that's equal to 0.05. However, both the numbers used will have to be same used in the 0.05 and 1. So it can be like (x+\-___)(x+\-_____)

Looking for something else?

Not the answer you are looking for? Search for more explanations.