anonymous
  • anonymous
log9 9 ? need help please and thankyou"EXPLAIN TO ME" A.log9 4 + log9 5 B.log4 3 + log5 3 C.log9 3 + log9 3 D.log3 9 + log3 9
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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jdoe0001
  • jdoe0001
log9 4 + log9 5 is it supposed to be \(\huge log9^4 + log9^5\ \ ?\)
anonymous
  • anonymous
YES @jdoe0001
jdoe0001
  • jdoe0001
http://www.teachengineering.org/collection/van_/lessons/van_bmd_less2/log_properties_lesson2_fig2.jpg take a peek at the Product rule

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jdoe0001
  • jdoe0001
shoot, not that one hehe
jdoe0001
  • jdoe0001
the POWER rule rather
jdoe0001
  • jdoe0001
well, both really :)
anonymous
  • anonymous
OKAY I SAW THE RULE
jdoe0001
  • jdoe0001
and those 2 rules is all you need for all those
anonymous
  • anonymous
NO I DONT HAVE TO SOLE ALL OF THOSE THERE THE ANSWERS IM SUPPOSE TO BE EVALUATION LOG9 9 @jdoe0001
jdoe0001
  • jdoe0001
ohh, ok then you only need the product rule
anonymous
  • anonymous
IM KIND OF CONFUSED ON HOW IM SUPPOSE TO DO THIS ?
anonymous
  • anonymous
@jdoe0001
jdoe0001
  • jdoe0001
$$ log\color{blue}{9^4} + log\color{green}{9^5}\\ log_b(\color{blue}{n}) + log_b(\color{blue}{\color{green}{m}}) = log_b(\color{blue}{n}\times \color{green}{m}) $$
anonymous
  • anonymous
I GOT D TO BE MY ANSWER @jdoe0001
jdoe0001
  • jdoe0001
well, you may wan to check your exponent rules too http://www.math-play.com/image-exponents-rules.jpg
jdoe0001
  • jdoe0001
see the 1st one, in yellow?
jdoe0001
  • jdoe0001
hmmm, wait ... lemme recheck ... myself
anonymous
  • anonymous
YES @jdoe0001
jdoe0001
  • jdoe0001
so,.... yeah, the 1st in yellow
anonymous
  • anonymous
I GT MY ANSWERTO BE (D) @jdoe0001
jdoe0001
  • jdoe0001
D: is $$ log3^9 + log3^9 \implies log3^{9+9} \implies log3^{18} $$
anonymous
  • anonymous
IT'S C @jdoe0001
jdoe0001
  • jdoe0001
C: wouild be $$ log9^3 + log9^3 \implies log9^{3+3} $$
anonymous
  • anonymous
C DOESN'T HAVE ^2 IT HAS 9
jdoe0001
  • jdoe0001
hmm, doesn't show in your lines up there
jdoe0001
  • jdoe0001
C.log9 3 + log9 3
anonymous
  • anonymous
YYES @jdoe0001
jdoe0001
  • jdoe0001
but anyhow, that's the Product rule
jdoe0001
  • jdoe0001
C.log9 3 + log9 3 I assumed it to be \(log9^3 + log9^3 \implies log9^{3+3}\)

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