anonymous
  • anonymous
Please solve 4x - 6x^3 + 6/12x My mom is making me do summer math questions and she decided to have me do this but I'm stuck...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Loser66
  • Loser66
My mom gives me exactly that problem but there is something after that chain of letter, like = 0 . Since my mom's stuff doesn't look like your mom's one. I don't know how to do with yours.
anonymous
  • anonymous
I think she wrote it wrong... did you're mom give you something close?
Loser66
  • Loser66
it's hers 4x -6x^3 +6/12x=0 and asks me solve it. it is different from yours, right?

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More answers

anonymous
  • anonymous
She said that she "was rushed and chopped it off... sorry." And now im looking at the problem but is it possible to divide 4x by 12x and =0?
whpalmer4
  • whpalmer4
Here's how to solve \[4x-6x^3+\frac{6}{12}x=0\] My able assistant will take over at this point :-)
Loser66
  • Loser66
show me more, britanny. my mom says " factor" or something like that
anonymous
  • anonymous
I got as far as: 4x - 6x^3 + 6 /12 /12 /12 3 - 2^3 + 6
blurbendy
  • blurbendy
is it supposed to be: |dw:1371343149484:dw| or as whpalmer4 showed?
anonymous
  • anonymous
*with the /12's bumped over a bit but yeah
Loser66
  • Loser66
hey britanny, where your x , why it disappears?
anonymous
  • anonymous
I dunno...?
Loser66
  • Loser66
ok, let him do
whpalmer4
  • whpalmer4
@blurbendy judging from the solution to that, the answer is no :-) \[\left\{x\to \frac{1}{9} \left(\left(\frac{729}{2}-\frac{27 \sqrt{697}}{2}\right)^{1/3}+3 \left(\frac{1}{2} \left(27+\sqrt{697}\right)\right)^{1/3}\right)\right\},\]\[\left\{x\to -\frac{1}{18} \left(1+i \sqrt{3}\right) \left(\frac{729}{2}-\frac{27 \sqrt{697}}{2}\right)^{1/3}-\frac{1}{6} \left(1-i \sqrt{3}\right) \left(\frac{1}{2} \left(27+\sqrt{697}\right)\right)^{1/3}\right\},\]\[\left\{x\to -\frac{1}{18} \left(1-i \sqrt{3}\right) \left(\frac{729}{2}-\frac{27 \sqrt{697}}{2}\right)^{1/3}-\frac{1}{6} \left(1+i \sqrt{3}\right) \left(\frac{1}{2} \left(27+\sqrt{697}\right)\right)^{1/3}\right\}\]
blurbendy
  • blurbendy
lol
anonymous
  • anonymous
woah you just made it even more complicated!
whpalmer4
  • whpalmer4
@britanny_ No, that's the solution to the equation that @blurbendy was asking about. I think it is safe to say that your mom isn't asking you to solve any cubics like that :-)
anonymous
  • anonymous
oah! Ok.. you scared me for a second!
whpalmer4
  • whpalmer4
or if she is, it's going to be a long summer for you :-)
anonymous
  • anonymous
_-_
anonymous
  • anonymous
:3
blurbendy
  • blurbendy
I got 9x/2 -6x^3
blurbendy
  • blurbendy
that's just simplifying it though. do you want to solve for x too?
anonymous
  • anonymous
no just how you would check your answer please!
whpalmer4
  • whpalmer4
Didn't your mom ask you to solve? That's what you wrote initially...
whpalmer4
  • whpalmer4
Can you factor \[\frac{9}{2}x-6x^3=0\]any more?
anonymous
  • anonymous
No thank you!
jim_thompson5910
  • jim_thompson5910
If the problem is \[\large \frac{4x - 6x^3 + 6}{12x}\] and you want to simplify then you can factor out the GCF 2 from the numerator to get 2(2x-3x^3+3) and you can factor 12x into 2*6x ----------------------------------------------- so \[\large \frac{4x - 6x^3 + 6}{12x}\] turns into \[\large \frac{2(2x - 3x^3 + 3)}{2*6x}\] and the two '2's cancel leaving you with \[\large \frac{2x - 3x^3 + 3}{6x}\]
anonymous
  • anonymous
Thanks @jim_thompson5910 and @whpalmer4 and @blurbendy and @Loser66
jim_thompson5910
  • jim_thompson5910
yw

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