Alright lets try a fun one. It costs a family of 8 a total of $209 for general admission tickets to the Mexican City Zoo. How many adult tickets and how many child tickets were purchased? GOGOGO!
Stacey Warren - Expert brainly.com
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I believe it's Impossible to know without knowing the price of each adult and each child ticket...
Well we don't know 1. How many children/adults and 2. How much the tickets are (either or)
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i was trying to upload a file but internet went dumb on me my bad
So we know
A + C = 8
33A + 22C = 209
solve the system...
So lets solve for adults first
C = 8 - A
plug that into the second equation
33A + 22(8 - A) = 209
33A + 176 - 22A = 209
33A - 22A = 11A
11A + 176 = 209
11A = 33
A = 3
There are 3 adults...how many kids?
nice job im impressed. What property did you just used?
It is called "substitution"
by God i could not solve it oh well thanks!
When you have a system like that....you solve for 1 variable...that way you can substitute that in...and solve for the other variable as I did :)
If you need anymore help / explanation feel free to message me :)