anonymous
  • anonymous
g(x)=sqrt x+2 ; x=-2,-2,2,7 @jim_thompson5910
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
so starting with x=-2 i would get g(-2)=sqrt-2+2 so it'd be g(-2)=sqrt0????????????
jim_thompson5910
  • jim_thompson5910
the square root of 0 is _____
anonymous
  • anonymous
0

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jim_thompson5910
  • jim_thompson5910
I'm assuming the function is \[\large g(x) = \sqrt{x+2}\]
jim_thompson5910
  • jim_thompson5910
so (-2,0) is on the graph
anonymous
  • anonymous
yup
anonymous
  • anonymous
o
anonymous
  • anonymous
:)
anonymous
  • anonymous
would the domain be all real numbers too?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
there are some numbers that will not work
jim_thompson5910
  • jim_thompson5910
in general, you cannot take the square root of a negative number to get a real number as an output
jim_thompson5910
  • jim_thompson5910
so if x+2 is negative, then it won't work this means you have to make x+2 either 0 or positive
anonymous
  • anonymous
x>=-2 is the domain?
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
you can also see the domain when you graph (like you saw the range)
anonymous
  • anonymous
and the range would be y>=0
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
ty!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jim_thompson5910
  • jim_thompson5910
sure thing
anonymous
  • anonymous
how is the graph suppose to look?
anonymous
  • anonymous
|dw:1371344439597:dw|something like that?
jim_thompson5910
  • jim_thompson5910
something like this |dw:1371344439145:dw|
jim_thompson5910
  • jim_thompson5910
probably more shallow
anonymous
  • anonymous
yup got that :)
jim_thompson5910
  • jim_thompson5910
ok great
anonymous
  • anonymous
what about if it looks like h(x)=|x|+4 x=-3,-2,-1,0,1,2,3
anonymous
  • anonymous
the first one would just be -3+4 right?
jim_thompson5910
  • jim_thompson5910
same idea, plug in values of x to get corresponding y values
anonymous
  • anonymous
Those paranthesis |-3| don't mean anything different do they?
jim_thompson5910
  • jim_thompson5910
keep in mind that |x| is either 0 or positive (and never negative)
jim_thompson5910
  • jim_thompson5910
|-3| = 3
jim_thompson5910
  • jim_thompson5910
|-22| = 22 |-108| = 108 etc etc
jim_thompson5910
  • jim_thompson5910
it is asking "what is the distance from -22 to 0?" well the answer is 22 units, so |-22| = 22
anonymous
  • anonymous
ooooo glad I asked :)
anonymous
  • anonymous
so it'd be 3+4
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
good to know :)
anonymous
  • anonymous
would the range be all real numbers
anonymous
  • anonymous
i mean domain
anonymous
  • anonymous
and range would be y>=4
anonymous
  • anonymous
so domain is all real numbers, range is y>=4 @jim_thompson5910
anonymous
  • anonymous
and should my graaph be a v?
jim_thompson5910
  • jim_thompson5910
domain: set of all real numbers range: y >= 4 graph is a V shaped graph so you're correct on all 3
anonymous
  • anonymous
:)
anonymous
  • anonymous
@jim_thompson5910 what if the problem was f(x)=8; x=-3,-2,-1,0,1,2,3 the domain would be all real numbers the range would be y=8
jim_thompson5910
  • jim_thompson5910
yep and you basically would have a flat horizontal line going through y = 8 on the y axis
anonymous
  • anonymous
yup
anonymous
  • anonymous
what if it was g(x)=x^3-4; x=-3,-2,-1,0,1,2,3
anonymous
  • anonymous
the domain would be all real numbers the range would be y>=-31 right @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
with any cubic, the domain and range are the same and they are both the set of all real numbers
anonymous
  • anonymous
wait so the domain and range are both all real numbers?
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
yes
jim_thompson5910
  • jim_thompson5910
this is true with any cubic function
jim_thompson5910
  • jim_thompson5910
and any linear function (that's not horizontal and not vertical)
anonymous
  • anonymous
how would this graph look? I gotta squiggle?
jim_thompson5910
  • jim_thompson5910
something like this |dw:1371348286135:dw|
anonymous
  • anonymous
yup squiggle lol ty so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
jim_thompson5910
  • jim_thompson5910
yw

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