g(x)=sqrt x+2 ; x=-2,-2,2,7
@jim_thompson5910

- anonymous

g(x)=sqrt x+2 ; x=-2,-2,2,7
@jim_thompson5910

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- anonymous

so starting with x=-2
i would get g(-2)=sqrt-2+2
so it'd be g(-2)=sqrt0????????????

- jim_thompson5910

the square root of 0 is _____

- anonymous

0

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## More answers

- jim_thompson5910

I'm assuming the function is \[\large g(x) = \sqrt{x+2}\]

- jim_thompson5910

so (-2,0) is on the graph

- anonymous

yup

- anonymous

o

- anonymous

:)

- anonymous

would the domain be all real numbers too?

- jim_thompson5910

no

- jim_thompson5910

there are some numbers that will not work

- jim_thompson5910

in general, you cannot take the square root of a negative number to get a real number as an output

- jim_thompson5910

so if x+2 is negative, then it won't work
this means you have to make x+2 either 0 or positive

- anonymous

x>=-2 is the domain?

- jim_thompson5910

good

- jim_thompson5910

you can also see the domain when you graph (like you saw the range)

- anonymous

and the range would be y>=0

- jim_thompson5910

yep

- anonymous

ty!!!!!!!!!!!!!!!!!!!!!!!!!!!!

- jim_thompson5910

sure thing

- anonymous

how is the graph suppose to look?

- anonymous

|dw:1371344439597:dw|something like that?

- jim_thompson5910

something like this
|dw:1371344439145:dw|

- jim_thompson5910

probably more shallow

- anonymous

yup got that :)

- jim_thompson5910

ok great

- anonymous

what about if it looks like h(x)=|x|+4
x=-3,-2,-1,0,1,2,3

- anonymous

the first one would just be -3+4 right?

- jim_thompson5910

same idea, plug in values of x to get corresponding y values

- anonymous

Those paranthesis |-3| don't mean anything different do they?

- jim_thompson5910

keep in mind that |x| is either 0 or positive (and never negative)

- jim_thompson5910

|-3| = 3

- jim_thompson5910

|-22| = 22
|-108| = 108
etc etc

- jim_thompson5910

it is asking "what is the distance from -22 to 0?" well the answer is 22 units, so |-22| = 22

- anonymous

ooooo glad I asked :)

- anonymous

so it'd be 3+4

- jim_thompson5910

yes

- anonymous

good to know :)

- anonymous

would the range be all real numbers

- anonymous

i mean domain

- anonymous

and range would be y>=4

- anonymous

so domain is all real numbers,
range is y>=4
@jim_thompson5910

- anonymous

and should my graaph be a v?

- jim_thompson5910

domain: set of all real numbers
range: y >= 4
graph is a V shaped graph
so you're correct on all 3

- anonymous

:)

- anonymous

@jim_thompson5910 what if the problem was f(x)=8; x=-3,-2,-1,0,1,2,3
the domain would be all real numbers
the range would be y=8

- jim_thompson5910

yep and you basically would have a flat horizontal line going through y = 8 on the y axis

- anonymous

yup

- anonymous

what if it was g(x)=x^3-4; x=-3,-2,-1,0,1,2,3

- anonymous

the domain would be all real numbers
the range would be y>=-31
right @jim_thompson5910

- jim_thompson5910

with any cubic, the domain and range are the same and they are both the set of all real numbers

- anonymous

wait so the domain and range are both all real numbers?

- anonymous

@jim_thompson5910

- jim_thompson5910

yes

- jim_thompson5910

this is true with any cubic function

- jim_thompson5910

and any linear function (that's not horizontal and not vertical)

- anonymous

how would this graph look? I gotta squiggle?

- jim_thompson5910

something like this
|dw:1371348286135:dw|

- anonymous

yup squiggle lol ty so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

- jim_thompson5910

yw

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