anonymous
  • anonymous
Use basic identities to simplify the expression. (tan(θ))/(cot(θ))
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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zzr0ck3r
  • zzr0ck3r
(a/b)/(b/a) = (a/b)(a/b)
anonymous
  • anonymous
a=tan b=cot?
zzr0ck3r
  • zzr0ck3r
a = sinx, b = cosx (sinx/cosx)/(cosx/sinx) = sinx*sinx/cosx*cosx = sin^2(x)/cos^2(x)

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zzr0ck3r
  • zzr0ck3r
sin^2(x) + cos^2(x) = 1 divide everything by cos^2(x) and you have (sin^2(x)/cos^2(x)) = sec^2(x) -1
anonymous
  • anonymous
what is sec^2(x)-1 equal too because that is not an option?
anonymous
  • anonymous
options are: sec2θ sin θ tan2θ cos3θ
zzr0ck3r
  • zzr0ck3r
many things, what are the options
zzr0ck3r
  • zzr0ck3r
tan^2(x) = sin^x*sin^x/cos^x*cos^2x
anonymous
  • anonymous
tank you!
zzr0ck3r
  • zzr0ck3r
tan^2(x) = sin^2xsin^2x/cos^2x*cos^2x
anonymous
  • anonymous
thank*
zzr0ck3r
  • zzr0ck3r
np

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