anonymous
  • anonymous
The potential diffrence across circuit is 200 v is it same fr all apaitors in series connection or do v have to find its sepertely??? the circuit is drawn below sorry lil untidy fig.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
No, it is not same. For the 2nd line the charges in the capacitors are the same. The potential difference is found by q/C Now try solving.
anonymous
  • anonymous
but q is not gvn frst line n last line c is 100 n second line its 200 the potential difference overol is 300v

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anonymous
  • anonymous
m confused
IrishBoy123
  • IrishBoy123
the charge on the capacitors in series (the middle leg of your circuit) will be the same, because they are directly connected. however, the voltage on that leg will be split across the capacitors according to capacitance. much in the same way as they would be split across resistors in series, but according to a different formula. let total voltage across that leg VT = V1 + V2. VT also = QT/CT which also = Q1/C1 + Q2/C2 = Q/C1 + Q/C2 because the charge (Q) has to be the same ie Q1 = Q2. {do you know why the charge on capacitors in series has to be the same?} therefore, 1/CT = 1/C1 + 1/C2. so whilst, as with resistors in series, the voltage drop is shared across the capacitors in series, the formula for combining their capicitances (C) is more akin to the formule for combining resistors in series. i hope this is helpful rather than confusing.

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