Prove that the product of any r consecutive numbers is divisible by r! .
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yes r factorial
Well i'm not sure I know the answer to this question but maybe we can work together. I know that 5! is 1x2x2x4x5 so now we know that r! is.
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Here, http://www.physicsforums.com/showthread.php?t=176717 that could probably help you. c:
Kirby, where'd you get 5?
well.. it would have to be divisible by r!
if you have 5 consecutive numbers, lets say 10/11/12/13/14
then 5! = 5*4*3*2*1
you can notice 12 is divisible by 3*4, 10 by 5*2
Thank you Sir
well i typed out a fairly nice post showing exactly what I meant, but my comp froze and I lost it all
point was, for any length r, you will create a series of consecutive numbers such that r! is a factor in every one (except primes, of course)
because the values along your length r depend on r itself