anonymous
  • anonymous
which graph is shown below? A. y=tan2x B. y=3cos4x C. y=Sin(x+pi) D. y=-2-cos(x-pi)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
IrishBoy123
  • IrishBoy123
the y-zeroes are at 0, π, 2π etc: what is tan(2*0), tan(2*π), etc what is cos(4*0), cos(4*π), etc what is sin(1*0), sin(1*π), etc the curves peak/ trough at 1/-1, and are symmetrical about the x-axis. that must count for something too. they have not been shifted around. you can work this out from this and any other clues you might find. cos(x-π)!! that is interesting too. that shifts the cos curve back by π on the x-axis. however the final option also shifts the curve on the y-axis as it is "-2-cos(x-pi)". that means, surely, that the y values must be between -1 and -2?!?!
anonymous
  • anonymous
is it C?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

whpalmer4
  • whpalmer4
Test some values. 0 is a good one. Does 0 in the formula for C give you the right y-value, judging from the graph?
jkristia
  • jkristia
You know the graph is continuous, so that excludes. Then you know that the range is +- 1, so the amplitude is 1 and the amplitude of cos and sin is1, so that excludes... which one. Finally you know the graph is is centered at y = 0, so that excludes ...? Then you have one left.
whpalmer4
  • whpalmer4
As a favorite math teacher used to say whenever someone offered up an answer like "is it C?" — "is that an answer, or a prayer?" :-)
anonymous
  • anonymous
lol prayer
anonymous
  • anonymous
if x=0 y should = 0 too right? based on the graph
anonymous
  • anonymous
@whpalmer4
jkristia
  • jkristia
if you think the answer is C then try insert x = 0 Sin(0+pi) = ? sin(0) = 0, sin(pi/2) = 1 sin(pi) = ?
whpalmer4
  • whpalmer4
C is correct. We've ruled out A because the graph of tan doesn't look like a sine curve. We can rule out B because the amplitude of the curve is wrong - it goes from -3 to 3 instead of -1 to 1 like our graph. D can be ruled out because it has an offset of -2 and even without the offset, the phase is wrong, because cos(x-pi) at x = 0 is -1, and our curve needs to go through (0,0). That leaves C, y = sin(x+pi). At x = 0, sin(0+pi) = sin(0) = 0, so that matches our graph. At x = pi, sin(pi+pi) = 0, and that also matches our graph. Not only is it the correct answer by process of elimination, it actually matches :-)

Looking for something else?

Not the answer you are looking for? Search for more explanations.