the line passes through the orgin and has a slope of 4. what is the equation of the line that is parallel to the first line and passes through the point (1,-2)
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(0,0) and m=4
Similarly you have points and m in 2nd case as well
Let the equation of the original line be y=mx+c where m is the slope of the line and(x,y) is the required point....
now since the line passes through origin....so origin satisfies the equation of the line...
thus we get y=mx
in this case m=4
thus eqution of original line is y=4x
now we have the find the equation of such a line which is parallel to the above line .....(parallel lines have same slope)
so the slope of this line is also equal to 4
secondly it passes through (1,-2)...therefore
thus the final equation of the new line is y=4x-6...(in slope form)