anonymous
  • anonymous
Solve: 112=-16t^2+128t
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I know you get two separate answers but I'm not sure the steps to get there.
hartnn
  • hartnn
can you bring that in the form of \(ax^2+bx+c = 0 \)
hartnn
  • hartnn
by adding 16t^2-128t on both sides.

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More answers

anonymous
  • anonymous
yes so, -16t^2+128t-112=0 or -16t^2-128t+112
anonymous
  • anonymous
sorry i forgot the =0 on the second one
hartnn
  • hartnn
ok, you brought 112 on other side, -16t^2 +128t-112 =0 is correct, but how about 16t^2 -128t+112 = 0 ?
anonymous
  • anonymous
wouldn't you get the same answer?
hartnn
  • hartnn
ofcourse ! and now can you simplify that a bit before proceeding ? notice that you can divide the entire equation by 16 and make those large numbers like 128,112....small
hartnn
  • hartnn
16t^2 -16*8t +16*7 =0 ----->t^2 -8t +7=0 got this ?
anonymous
  • anonymous
yes that's what i got
hartnn
  • hartnn
t^2 -8t +7=0 is relatively simple to solve can you think of 2 numbers whose product is 7 and sum is -8 ??
anonymous
  • anonymous
that would factor out to (t-7) (t-1) right?
hartnn
  • hartnn
absolutely correct :)
hartnn
  • hartnn
(t-7) (t-1) =0 gives you which 2 values of t ?
anonymous
  • anonymous
1 and 7?
hartnn
  • hartnn
good! thats your answer :)
anonymous
  • anonymous
THANK YOU!
hartnn
  • hartnn
welcome ^_^

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