anonymous
  • anonymous
How do I identify the slope and y-intercept of the line, ex:8x-2y=8
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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eSpeX
  • eSpeX
Slope-intercept of a line is \(y=mx+b\), put your equation into that form and you will have your answers.
anonymous
  • anonymous
so -2y=8x+8
anonymous
  • anonymous
so that would simplify to y=-4x-4

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anonymous
  • anonymous
so the y intercept would be -4x-4 and the slope would be -4 @eSpeX ?
eSpeX
  • eSpeX
Close, you want to pay closer attention to your signs. \[8x-2y=8\rightarrow-2y=-8x+8\rightarrow y=\frac{-8x}{-2}+\frac{8}{-2}\] and so that would simplify to \(y=4x-4\)
anonymous
  • anonymous
so y intercept is 4x-4 and slope is 4?
eSpeX
  • eSpeX
In the equation, y=mx+b, 'b' is your y-intercept and m is your slope. So your slope is 4, and your y-intercept is?
anonymous
  • anonymous
-4
anonymous
  • anonymous
so y intercept is 4x-4 and slope is -4
eSpeX
  • eSpeX
Exactly. Because if 'x' is 0, then you are on the 'y' axis. So if y=4(0)+b, then the y coordinate is y=b
anonymous
  • anonymous
gotcha thanks!!!!!!!!!!!!!!!
eSpeX
  • eSpeX
You're welcome.
anonymous
  • anonymous
@eSpeX how would the graph for this look?
anonymous
  • anonymous
would it be similar to this
eSpeX
  • eSpeX
It would be similar in the sense that the image also shows a line with a positive slope. In your problem you have a slope of 4 and a y-intercept of -4. Since \(m=\frac{rise}{run}\), you have 4=\(\frac{4}{1}\). Starting at your intercept point, (0,-4), you would rise up 4 and run to the right 1 between every point on your line.
anonymous
  • anonymous
ty!!!!!!!!!!!!!!!!!!!!!!!!
eSpeX
  • eSpeX
You're welcome @aprilsages

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