anonymous
  • anonymous
-2(y-4)-(3y-2)=-2-(6y-2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ivettef365
  • ivettef365
First solve what is in parenthesis
anonymous
  • anonymous
-2y-8-3y-2=-2-(6y-2)
ivettef365
  • ivettef365
actually it is -2y+8-3y+2 = -2-6y+2

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ivettef365
  • ivettef365
Now combine like terms
anonymous
  • anonymous
1y+6 = -2-(6y-2)?
ivettef365
  • ivettef365
-2y -3y = -5y 8 + 2 = 10 so you have -5y+10 = -2 +y +2 now do the same on the other side
ivettef365
  • ivettef365
sorry I meant -5y +10 = -2 -6y +2
anonymous
  • anonymous
I do not see the +10 when -2y+(-3y)+8-2
ivettef365
  • ivettef365
lets start you have -2(y-4)-(3y-2) = -2-(6y-2) -2y+8-3y+4 = -2-6y+2
ivettef365
  • ivettef365
(-2)(y)=-2y (-2)(-4) = positive 8 (-)(3y) = -3y (-)(-2) = positive 2 can you see it ??
ivettef365
  • ivettef365
sorry it is -2y+8-3y+2 = -2-6y+2
ivettef365
  • ivettef365
now you combine like terms -2y-3y = -5y and 8+2 = 10
ivettef365
  • ivettef365
now you have -5y+10 = -6y (because -2+2=0)
ivettef365
  • ivettef365
Hope you can take it from there, I have to go
anonymous
  • anonymous
Thank you for your help

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