anonymous
  • anonymous
I have the graphs, I just need to know how to describe the end behaviors.....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Graph the function f(x) = –3x3 + 9x2 – 2x + 3 using graphing technology and describe the end behavior. (1 point) Graph the function f(x) = x4 – 7x3 + 12x2 + 4x – 12 using graphing technology and describe the end behavior. (1 point) Without using technology, describe the end behavior of f(x) = –3x38 + 7x3 – 12x + 13. (1 point) Using complete sentences, explain how to find the zeros of the function f(x) = 2x3 – 9x + 3. (2 points) Create your own polynomial with a degree greater than 2. Attach the graph to the word document and find the zeros of the function. (3 points)
anonymous
  • anonymous
the end behavior is what happens with the graph when x grows so much this is x->INF
anonymous
  • anonymous
how do I put that into a sentence though?

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anonymous
  • anonymous
u must write something like this "Down" on the left and "up" on the right.
anonymous
  • anonymous
okay, so i just describe how the line curves and stuff?
anonymous
  • anonymous
mmm yes but make the first one to make sure that u r doing it right
anonymous
  • anonymous
so this is the graph and I would say something along the lines of: the function starts in the upper left of the graph and at (0,3) it curves up until at (1,11) it curves back down into the bottom right?
anonymous
  • anonymous
does that make any sense?
anonymous
  • anonymous
mmm no just the end behavior for this graph it is up on the left and down to the right
anonymous
  • anonymous
i dont understand, sorry
anonymous
  • anonymous
see what happens when x is negative
anonymous
  • anonymous
the graph goes upward right¡?
anonymous
  • anonymous
right
anonymous
  • anonymous
and what happen when x is positive and grows so much
anonymous
  • anonymous
it extends downward?
anonymous
  • anonymous
yes so did u get it now? it is donw to the right
anonymous
  • anonymous
is that all i say?
anonymous
  • anonymous
yes it is what u need to say
anonymous
  • anonymous
okay, I understand. thank you!
anonymous
  • anonymous
ok any question write it here
anonymous
  • anonymous
okay, thanks!

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