anonymous
  • anonymous
Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 4x − ___
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
i dont no da answer
anonymous
  • anonymous
then why did you comment? lol
whpalmer4
  • whpalmer4
The vertex form of a parabola which opens up or down is \[(x-h)^2=4p(y-k)\]with a focus at \((0,p)\) and vertex at \((h,k)\). To get the standard form (what you have), just multiply it out after plugging in the numbers. Then you'll have to solve for the value of \(p\) that makes y=0 when x = 2 or y = 0 when x = -6.

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anonymous
  • anonymous
thanks so much!
whpalmer4
  • whpalmer4
Did you get an answer?
anonymous
  • anonymous
yes thank you my mom helped me but thanks for the help anyways
whpalmer4
  • whpalmer4
what did you get for the answer?

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