anonymous
  • anonymous
4x-6y=2 5x+3y=1 Solve the system using any algebraic method
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Use the Elimination Method. If you look at the y's you will see that if you multiply the second equation by the first you will have opposites, so multiply the second equation by 2.
anonymous
  • anonymous
why multiply by 2?
anonymous
  • anonymous
\[4x-6y=2\] \[10x+6y=2\]

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anonymous
  • anonymous
to use elimination you need to have the numbers in front of one of the variables either the same or with just different signs, and the best way to do that is to multiply the second equation by 2, make sense?
anonymous
  • anonymous
And so I get 10x+6y=2? y= 1/7 right?
anonymous
  • anonymous
oh i see okay :p
anonymous
  • anonymous
so now you are going to add together the two equations and by doing this the y will go away
anonymous
  • anonymous
\[14x=4\]
anonymous
  • anonymous
and you divide both sides by 14, correct?
anonymous
  • anonymous
yeah, and so x will be 1/7, not y.
anonymous
  • anonymous
to find y you just plug in x=1/7 to either of the original equations and solve for y
anonymous
  • anonymous
okay I get it now, thanks
anonymous
  • anonymous
Welcome
anonymous
  • anonymous
I have a similar problem to that, do I do the same thing to it also
anonymous
  • anonymous
The problem is 4x+6y=8 2x+3y=3
anonymous
  • anonymous
Ok, so you need to look at the numbers in front of the letters. Is there any pair that you can multiply one of the numbers to get the other number?
anonymous
  • anonymous
-2?
anonymous
  • anonymous
to cancel out the x
anonymous
  • anonymous
Good, so that would be multiplying the second equestion by -2. Go ahead, this one is going to be tricky, but don't worry.
anonymous
  • anonymous
I got 4x+6y=8 -4x+3y=-6, so would it be no solution
anonymous
  • anonymous
You are correct that it would be no solution, you have a small error on your second equation, it should be -6y, incase you need to show your work.
anonymous
  • anonymous
yea thats what I meant to put, I have to go now, but I would really like it if you could message me or something so you could help me with all the other problems
anonymous
  • anonymous
You could follow me, i am not on that often now that it is summer.

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