anonymous
  • anonymous
a container contains 50 green tokens, 20 blue, and 3 red. 2 tokens are pulled randomely. Compute P(FIE). E-you select a non-blue first. F-the second is non-blue
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Can anyone help me?
Zarkon
  • Zarkon
without replacement?
anonymous
  • anonymous
yes

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anonymous
  • anonymous
Are you able to help me?
Zarkon
  • Zarkon
is this conditional prob...prob of F given E
anonymous
  • anonymous
I am not really sure..
Zarkon
  • Zarkon
\(P(F|E)\) so E has happened so a non-blue has been selected
anonymous
  • anonymous
I am finding P(FIE) =?
Zarkon
  • Zarkon
so there are now only 72 tokens remaining....how many anre non-blue?
Zarkon
  • Zarkon
*how many are non-blue?
anonymous
  • anonymous
still 20 ?
Zarkon
  • Zarkon
originally there were 53 non-blue
anonymous
  • anonymous
so then there are still 53 non-blue
Zarkon
  • Zarkon
no...event E has happened...a non-blue has been selected.
anonymous
  • anonymous
so 52
Zarkon
  • Zarkon
correct...so what is the probability?
anonymous
  • anonymous
52/72?
Zarkon
  • Zarkon
correct
anonymous
  • anonymous
and that is the answer?
anonymous
  • anonymous
that was simple!

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