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How do you find the area of a rectangle?
Length times width
So \(l\times w=area\), fill in what you know.
So it would be 9 times x right since we don't know the length
Exactly. That would also be equal to 153 since they give you the area.
So how do you find x?
9x=153, how do you isolate x?
I would divide right
Indeed you would, and your answer would be?
Hmm well I don't have a calculator with me so I'm stuck
How many times does 9 go into 15?
Since 15 is larger than 9, I would say that your answer is incorrect. In my drawing, 9 goes into 1, 0 times.
Aw I thought I said 0
You did say 0, but the question was how many times can 9 go into 15.
Yea I said 0 cause I looked at your drawing so it's 1
Right. |dw:1371517340009:dw| How many times will 9 go into 63?
I think 6
Right, plus 9?
Yes, so you just determined that 9 * 6 = 54. Now, plus 9 again?
Aw it goes into it 7 times
Exactly, and all without a calculator. :)
So you have|dw:1371517898863:dw| So your 'w' value for this rectangle is?
that's the w value right?
Since the area is l*w=153, and you just said that 9*7=63, I'm going to say that w does not equal 7.
Aw ok so we're not done yet
No, we're done, you just need to look closer. :D
Alright so you subtracted 63 from itself and got 0 now what's next
We hit 0, we're done. So what was the answer to 153 divided by 9?
oh it's 17... I knew that
I'm sure you did. :) So your rectangle is going to be l=9 and w=17
Alright thanks again but I also have another question
Okay, you going to make a new post or do it here?