anonymous
  • anonymous
What is the length of the hypotenuse of the triangle below?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1371516403250:dw|
anonymous
  • anonymous
\[a^2+b^2=c^2\]
anonymous
  • anonymous
try to solve it

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anonymous
  • anonymous
if you still have trouble i can help
anonymous
  • anonymous
\[9^2+9^2=c^2\]
anonymous
  • anonymous
So you get 162
anonymous
  • anonymous
Yes. Very good job.
jim_thompson5910
  • jim_thompson5910
a and b are 9*sqrt(2) not just 9
anonymous
  • anonymous
That is what i wrote
jim_thompson5910
  • jim_thompson5910
9^2 isn't the same as 9*sqrt(2) though
anonymous
  • anonymous
Jim is correct. The drawing has each leg labeled as \(9\sqrt{2}\). Your work treats each leg as only 9.
anonymous
  • anonymous
So it would be \[81^2\]?
anonymous
  • anonymous
Her approach is good though, Stephanie. If you have a right triangle and you know two of the three sides, plug the sides into \(a^2+b^2 = c^c\) and solve for the third side. Make sure the longest side is plugged into c in your equation.
GoldPhenoix
  • GoldPhenoix
\[\large \large (9\sqrt{2}^2) + (9\sqrt{2}^2) = h^2\]
anonymous
  • anonymous
Actually, no @GoldPhenoix \(\Large (9\sqrt{2})^2 + (9\sqrt{2})^2 = h^2\) And \(\Large (9\sqrt{2})^2\) simplifies to \(\Large9^2*\sqrt{2}^2\)
GoldPhenoix
  • GoldPhenoix
My bad. I thought my exponent was outside the parenthesis. =/
anonymous
  • anonymous
Easy mistake to make =)

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