anonymous
  • anonymous
Find the range of he inverse trigonometric function f(x)=tan^-1 (x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
you don't "find the range" you "define the range"
anonymous
  • anonymous
by convention the range of arcangent is \((-\frac{\pi}{2},\frac{\pi}{2})\)
anonymous
  • anonymous
how would you find that answer

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anonymous
  • anonymous
by looking in a book really i am not being silly tangent is periodic, so it is certainly not one to one you can make the inverse into a function by restricting the range of the inverse, which is the same as restricting the domain of tangent by convention the restriction is \((-\frac{\pi}{2},\frac{\pi}{2})\) that is just the convention, which is why you don't "find" it
anonymous
  • anonymous
okay i understand, so how would one define the range of he inverse trigonometric function f(x)=sin^-1 (x)
Mertsj
  • Mertsj
Same way...look in a book to see what mathematicians have decided to define as the range.
anonymous
  • anonymous
by convention it is \([-\frac{\pi}{2}, \frac{\pi}{2}]\) you need only look in a text, as @Mertsj said
anonymous
  • anonymous
thanks :)

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