anonymous
  • anonymous
Simplify 3a · 3b ÷ 3c ÷ 3d. Help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Use dem parentheses.
anonymous
  • anonymous
As stated, your question is ambiguous.
anonymous
  • anonymous
the abc and d are exponents

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anonymous
  • anonymous
if you do it from left to right
anonymous
  • anonymous
No, is it \(3b\div(3c\div3d)\) or \((3b\div3c)\div3d\)? These two are different things.
anonymous
  • anonymous
|dw:1371527789481:dw|
anonymous
  • anonymous
|dw:1371527864081:dw|
anonymous
  • anonymous
@timo86m That solution is not necessarily correct. We don't know the grouping.
anonymous
  • anonymous
dont need to if you just go from left to right.
anonymous
  • anonymous
That's not a safe assumption. I never did any left-to-right thing in college.
anonymous
  • anonymous
it is just order of operations perenthesis. In this case non exponents multiplication and division from left to right
anonymous
  • anonymous
Citations, please. I don't see it anywhere in this. http://en.wikipedia.org/wiki/Order_of_operations#The_standard_order_of_operations
anonymous
  • anonymous
it is always assumed left to right unless other wise stated by the perenthesis.
anonymous
  • anonymous
|dw:1371528260623:dw|
anonymous
  • anonymous
that is how i see the grouping anyhow.
anonymous
  • anonymous
So it's assumed that \(3^b\frac{1}{3^c}\frac{1}{3^d}\)?
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=3%5Ea+*3%5Eb+%C3%B7+3%5Ec%C3%B7+3%5Ed that is how wolfram sees it too.
anonymous
  • anonymous
Well, alright. I concede the point to you. But all this means is that whatever answer we give, there's a chance it's wrong because the original question was ambiguous.
anonymous
  • anonymous
|dw:1371528478926:dw|
anonymous
  • anonymous
draw it out @Scarr_Rose
anonymous
  • anonymous
3^a*3^b/3^c/3^d
anonymous
  • anonymous
draw it using the draw buttong silly :D
anonymous
  • anonymous
|dw:1371528774597:dw|
anonymous
  • anonymous
Oh my. Is that written exactly as you teacher gave it to you?
anonymous
  • anonymous
that is exactly how it looks in your book? If so then I am right :D
anonymous
  • anonymous
Or it could mean that the book is a really, really bad textbook.
anonymous
  • anonymous
|dw:1371528864889:dw|
anonymous
  • anonymous
That's still an ambiguity. Division is not commutative. http://en.wikipedia.org/wiki/Division_ring
anonymous
  • anonymous
well thats just what my questions is asking.
anonymous
  • anonymous
I am right @scarr lol :D
anonymous
  • anonymous
its not a text book its online school. but thanks @timo86m
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=a%C3%B7b*c%3Da*c%C3%B7b @sledgehammer if you preserve the division sign then it is :D
anonymous
  • anonymous
"Similarly, there can be ambiguity in the use of the slash ('/') symbol in expressions such as 1/2x. If one rewrites this expression as 1 ÷ 2 × x and then interprets the division symbol as indicating multiplication by the reciprocal, this becomes..." http://en.wikipedia.org/wiki/Order_of_operations#The_standard_order_of_operations
anonymous
  • anonymous
it isn't if a ÷ b = b ÷ a not true a*b ÷c = a ÷c * b is true notice the sign is preserved :D meaning it applies to the c and only the c
anonymous
  • anonymous
The ambiguity can't be removed, because the question as stated doesn't actually work in mathematics. As I linked to you, division is not commutative. So writing it out like that is necessarily ambiguous. WolframAlpha doesn't find it ambiguous because the syntax-reading grabs the next character only. It's like how TeX does it.
anonymous
  • anonymous
wolfram follows order of operations.
anonymous
  • anonymous
prove this statement wrong a×b/c = a/c b other than with c=0
anonymous
  • anonymous
Wolfram follows order of operations AND its own syntax. In other programming languages that only recognize strict order of operations, it will fail. \[\frac bca=\frac a{cb}\\b^2=1\]
anonymous
  • anonymous
IN fact this is true too a*b*c/d=a*b/d*c
anonymous
  • anonymous
No, it's not true, it's ambiguous. http://en.wikipedia.org/wiki/Division_ring
anonymous
  • anonymous
Dude I did not say a/(c*b) I said a/c b
anonymous
  • anonymous
That's why the original question should've included parentheses. Because you needed to write that out to make it clear.
anonymous
  • anonymous
You should've written (a/c)b and not a/c b, because the first has a precise meaning, and the second does not.

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