• anonymous
The equation for the motion of a projectile fired straight up at an initial velocity of 64 ft/s is h = 64t - 16t2, where h is the height in feet and t is the time in seconds. Find the time the projectile needs to reach its highest point. How high will it go?
  • Stacey Warren - Expert
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  • katieb
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  • phi
if you wrote this as \[ y = -16x^2 + 64 x \] do you notice it is a parabola ? using h for y and t for x. \[ h = -16t^2 + 64 t \] do you know how to find the vertex of a parabola ? The vertex will be the highest part This shows how to find the vertex
  • IrishBoy123
find dh/dt - which equals the vertical velocity of the projectile - and set that to zero. then solve for t, which gives you the time at which the thing stops rising. then plug that same t back into the original h(t) equation to find the max height.
  • anonymous
thanks i really appreciate the help :)

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