anonymous
  • anonymous
solve cos(2x-4)=sin(6x)
Meta-math
chestercat
  • chestercat
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RadEn
  • RadEn
what's interval for x ?
anonymous
  • anonymous
i have no clue, im doing the work sheet and that is all it says for this question
anonymous
  • anonymous
it says solve for x

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dan815
  • dan815
|dw:1371573363440:dw|
dan815
  • dan815
remember complimentary angles
anonymous
  • anonymous
the answer choices are 20, -11, 10.75, or 11.75
dan815
  • dan815
forget your answers, understand concept
RadEn
  • RadEn
if just in the 1st quadrant. u can use the identity : cosx = sin(90-x) cos(2x-4)=sin(6x) sin(90-(2x-4))=sin(6x) 90-(2x-4) = 6x solve for x the result would be same like @dan817 said :)
RadEn
  • RadEn
oppss 815 not 817, hihi :)
dan815
  • dan815
hi :)
dan815
  • dan815
do u see how complimentary angles work now
dan815
  • dan815
in a right angled triangle the 2 other angles must add up to 90
anonymous
  • anonymous
Im really slow at picking up these concepts.....:/ so this im reallly lost..
dan815
  • dan815
hmm how else can i explain it
anonymous
  • anonymous
btw i really appriciate the help you guysss!!
dan815
  • dan815
no lets do it between 4 to pi+4 for 1 interval of your cos(2x-4)
RadEn
  • RadEn
hmmm.. for easier, solve this algebrically :) can u solve for x, this part : |dw:1371574314002:dw|
dan815
  • dan815
first solve an x that works and ill show u how u can find all the other xs that work
anonymous
  • anonymous
|dw:1371574763654:dw|
anonymous
  • anonymous
cos(2x-4)=cos(90-6x) a)2x-4=90-6x+360k b)2x-4=6x-90+360k a)x=94/8+45k b)x=86/4+90k
anonymous
  • anonymous
x=11.75

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