jadekelllly
solve cos(2x-4)=sin(6x)
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RadEn
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what's interval for x ?
jadekelllly
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i have no clue, im doing the work sheet and that is all it says for this question
jadekelllly
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it says solve for x
dan815
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|dw:1371573363440:dw|
dan815
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remember complimentary angles
jadekelllly
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the answer choices are 20, -11, 10.75, or 11.75
dan815
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forget your answers, understand concept
RadEn
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if just in the 1st quadrant. u can use the identity :
cosx = sin(90-x)
cos(2x-4)=sin(6x)
sin(90-(2x-4))=sin(6x)
90-(2x-4) = 6x
solve for x
the result would be same like @dan817 said :)
RadEn
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oppss 815 not 817, hihi :)
dan815
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hi :)
dan815
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do u see how complimentary angles work now
dan815
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in a right angled triangle the 2 other angles must add up to 90
jadekelllly
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Im really slow at picking up these concepts.....:/ so this im reallly lost..
dan815
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hmm how else can i explain it
jadekelllly
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btw i really appriciate the help you guysss!!
dan815
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no lets do it between 4 to pi+4 for 1 interval of your cos(2x-4)
RadEn
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hmmm.. for easier, solve this algebrically :)
can u solve for x, this part :
|dw:1371574314002:dw|
dan815
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first solve an x that works and ill show u how u can find all the other xs that work
schadie
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|dw:1371574763654:dw|
Vitas
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cos(2x-4)=cos(90-6x)
a)2x-4=90-6x+360k
b)2x-4=6x-90+360k
a)x=94/8+45k
b)x=86/4+90k
Protien
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x=11.75