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gandalfwiz

  • 2 years ago

How to factor 8x^3 -125?

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  1. gandalfwiz
    • 2 years ago
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    It's part of a larger problem, 16x^5 -250x^2, and I saw that you could factor out a 2x^2 but don't know what to do next.

  2. tcarroll010
    • 2 years ago
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    You have the difference of 2 perfect cubes: \[a ^{3} - b ^{3} = (a - b)(a ^{2} + ab + b ^{2})\]where a = 2x and b = 5

  3. tcarroll010
    • 2 years ago
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    Once you make your substitutions for "a" and "b", you won't be able to factor\[a ^{2} + ab + b ^{2}\]unless you can go with complex number solutions.

  4. tcarroll010
    • 2 years ago
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    Hi Luis, and ughh, uhh, thanks! @Luis_Rivera

  5. gandalfwiz
    • 2 years ago
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    Oh, that makes sense. Thanks!

  6. tcarroll010
    • 2 years ago
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    uw!

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