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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\huge y=x^39x^2+15x+4\]
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
this is unfactorable?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.0
oh no wait nevermind
 one year ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Any particular method they want you to use? Do they specify factoring?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
No but isnt that the only way?
 one year ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Graphing is the easiest.
 one year ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Graph that bad boy. Look for where it crosses the x axis. Doneso.
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
no i have to use an algebraic method
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
because like say on an exam, i cant graph that
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Possible rational roots are :
 one year ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Okay then your best best is to use the rational root theorem to list possible rational roots. Then check each one to see if it is a valid root.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
\[\pm1,\pm4,\pm2\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Use synthetic division to see if any of those are actual roots.
 one year ago

SmoothMath Group TitleBest ResponseYou've already chosen the best response.0
Mertsj is correct. The way he got those possible roots is: A: Make a list of factors for the last number (In this case, it's 4) B: Make a list of factors for the first coefficient (In this case, it's 1) Possible rational roots must be of the form \(\huge \frac{\text{things in the first list}}{\text{things in the second list}}\)
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
It is not factorable.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So the best approach would be to find where y changes sign. Then you would know there is a root between those two values and you could hone in on it by trial and error. Of if you know calculus, you could use the derivative. What class is this for?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
@Mertsj calculus !
 one year ago

oldrin.bataku Group TitleBest ResponseYou've already chosen the best response.0
they want you to bruteforce using newton's more than likely
 one year ago
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