Help me find the derivative of this function

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Help me find the derivative of this function

Mathematics
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\[\huge A(t)= 20\sin^2(\frac{ t }{ 1000\pi })\]
Use power + chain rules
This is a very straightforward question.

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Other answers:

|dw:1371609626141:dw|
like that?
you forgot the final chain rule
|dw:1371609898205:dw|
@bahrom7893 what do you mean?
|dw:1371610057029:dw|
|dw:1371610058623:dw|
@bahrom7893 wait i dont get it tho, why the extra fraction :S
derivative of |dw:1371610223598:dw|
|dw:1371610328327:dw|
|dw:1371610801029:dw| @bahrom7893
Noooo
|dw:1371610749100:dw|
Guys stop confusing him. Burhan, your first answer was right. You just forgot to add in that fraction.
How do i simplify further ?
just use algebra, cancel out some fractions.
howww im really confused !!
The answer key says it should be \[\huge A'(t) = \frac{ 1 }{ 50\pi }\sin (\frac{ t }{ 50\pi })\]
2Sin(x)Cos(x) = ? (double angle formula)
if i just simplify that fraction to 'x' then =20((2sinx)(cosx)(x)) =20(xsinx)
.just use what I gave if you're still confused....
|dw:1371612098284:dw|
so according to our calculations, the answer should be: |dw:1371612290008:dw| which seemed right. the book might have a typo
........which is what I said 40 minutes ago........ |dw:1371612421231:dw|
lol
You're very welcome.
np my friend :)
b) What is the first value of t greater than 0 for which the derivative is equal to 0?
set the derivative equal to 0, then check the signs nearby
@primeralph what does that mean ^ ?
for it to equal zero, you have to shift t by the period pi
|dw:1371615489438:dw|

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